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What is an e1 in gsm?
e1 is a standard unit used to measure the amount of data flow. 1 e1 refers to 2mbps speed of data flow.
What is the fastest communication speed?
Radio Optical fiber Semaphore Heliostat Smoke signals American Sign Language TV remote control Garage-door opener Lantern in the belfry of Old North Church
What was the cruising speed of the fokker E1?
Cruising speed was 68 mph, with a maximum speed of 81 mph.
What is the speed of e1?
The E1 series high-speed train type had a maximum rated speed of 240 kph (~150 mph). They were operated by East Japan Railway Company (JR East) from July 1994 until September 2012.
What is the maximum speed of E1?
The E1 series high-speed train type had a maximum rated speed of 240 kph (~150 mph). They were operated by East Japan Railway Company (JR East) from July 1994 until September 2012.
What is the maximum speed of the e1 dedicated line?
An E1 dedicated line has a maximum speed of 2.048 Mbps. This standard digital transmission link can carry 30 voice channels along with one signaling channel and is commonly used in telecommunications for data and voice transmission.
How many E1 lines does PDH has?
There are 63 e1's in sdh STM-1 = 63 x E1; STM-4 = 63 x 4 E1; STM-16 = 63 x 16 E1; STM-64 = 63 x 64 E1.
There are 5 racing tracks and 25 horses At a time you can conduct race for 5 horses in the five available tracks What will be the minimum number of trials needed to find out the ultimate winner run?
Let's take an assumption, each horse runs at uniform speed every time. They all have different but fixed speed tag. Step 1) Divide the 25 horses into 5 groups. Each group will have 5 horses each. Step 2) Conduct 5 races for the 5 groups. Step 3) Conduct an another race with each group winners. (i.e. Fastest from Group 1, Fastest from Group 2, ... , and Fastest from Group 5) Step 4) Choose the winner from the Step 3. That will be fastest horse. (So, it needs only 6 races to find out the fastest horse of all the 25 horses) Additionally, Step 5) Name the horses as below: {a1,a2,..., a5}--> For the group which has the fastest horse after Step 3 (6th Race) {b1,b2,...,b5}---> For the group which has the 2nd fastest horse after Step 3 {c1,c2,...,c5}----> For the group which has the 3rd fastest horse after Step 3 {d1,d2,...,d5}---> For the group which has the 4th fastest horse after Step 3 {e1,e2,...,e5}---> For the group which has the 5th fastest horse after Step 3 Where according to their speed, a1>a2>..>a5; b1>b2>..>b5; c1>c2>..>c5; d1>d2>..>d5 and e1>e2>..>e5, also, a1>b1>c1>d1>e1, but not necessarily, b1>a2, c1>b2 etc. [Clearly a1 is the fastest horse] Step 6) Conduct a race with a2, a3, b1, b2 and c1 to find out the 2nd fastest and 3rd fastest of all the 25 horses. So, we need to conduct only 7 races to find out the top 3 fastest horses!
What are the Super Mario notes on xylophone?
Oh, what a happy little question! Playing the Super Mario notes on the xylophone can bring so much joy and creativity to your day. Just remember to start with the iconic melody and play around with the different notes until you find the perfect harmony that makes you smile. Happy xylophone playing, my friend!
Question paper of aptitute exam for engineering student?
Four engineering students E1, E2, E3 and E4 attempted their semester exams and their relative scores in Electronics, Computer Science, Mathematics and Communication is as follows: Electronics => E1> E2> E3> E4 Computer Science => E2> E4> E3> E1 Mathematics => E3> E1> E4> E2 Communication => E4> E2> E1> E3 The total marks for each of the tests was 100. It was also found that all students' scores were whole numbers and none scored marks less than 40. In addition, nobody scored the same marks in two subjects. The average marks scored by the four students were 70, 80, 60 and 80 respectively. 1. The total marks scored (all subjects inclusive) by E1 was ____? a) 200 b) 280 c) 320 d) 360
How do you calculate percentage reduction in expenses?
(E1 - E2)/E1 where E1 is the original expense and E2 is the new, lower expense.
How many E1 in STM-0?
STM-0= 21 E1 lines STM-1=(64x1) - 1 = 63 E1 lines STM-4=(64x4) - 4 = 252 E1 lines STM-16=(64x16) - 16 = 1008 E1 lines STM-64=(64x64) - 64 = 4032 E1 lines and so on
