Ultimately yes as the Mercury atoms rely on argon in the starter switch which heats the bimetallic strip to bend it making the switch close. This allows enough heat to be transferred to heat the filament electrodes. Then the argon in the starter unit stops conducting so the bimetallic switch closes causing the switch to open. The mains voltage now acts between the two electrodes which are hot enough for ionisation. This energy is used in the collision of mercury atoms with each other and with electrons in the tube.
Moonlight is almost entirely reflected sunlight, with very small amounts of reflected starlight and earthlight as well. As such, it radiates at the same continuous spectrum as the sun, though it won't have the bright emission lines that the sun emits.
Because the filament is extremely hot
phosphorescent materials do this
Aluminum or magnesium
Red light has less energy per photon than blue light, so to get the same energy we would need more red photons.
Because it doesn't emit light.
The moon itself does not emit light, we only see it because it reflects the sun's light towards us.
The moon itself does not emit light, we only see it because it reflects the sun's light towards us.
Moonlight is almost entirely reflected sunlight, with very small amounts of reflected starlight and earthlight as well. As such, it radiates at the same continuous spectrum as the sun, though it won't have the bright emission lines that the sun emits.
Because the filament is extremely hot
The core would emit light because it is hot. The outer atmosphere would absorb light because it is not completely transparent. It would also re-emit radiation itself, because of its heat.
phosphorescent materials do this
They emmit light because they have many stars.
Aluminum or magnesium
Red light has less energy per photon than blue light, so to get the same energy we would need more red photons.
Because the stars of Andromeda emit light
Yes because it only have light in common?