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No, only at one point, perpendicular to the radius
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If a circle of radius 2 is externally tangent to a circle of radius 8 what is the length of their common tangent?
the length of thr direct common tangent will be 2*{1/2 power of (r1*r2)} the answer will be 8 units in this case...
What are the tangent equations to the circle x2 plus y2 -6x plus 4y plus 5 equals 0 at the points where they meet the x axis?
Equation of circle: x^2 +y^2 -6x +4y +5 = 0 Completing the squares (x -3)^2 +(y +2)^2 = 8 Centre of circle: (3, -2) Radius of circle: square root of 8 Points of contact are at: (1, 0) and (5, 0) where the radii touches the x axis Slope of 1st tangent line: 1 Slope of 2nd tangent line: -1 Equation of 1st tangent: y -0 = 1(x -1) => y = x -1 Equation of 2nd tangent: y -0 = -1(x -5) => y = -x +5
What is the meaning of congruent circle?
2 circles that intersect each other
What is part of a circle between 2 points on a circle?
arc
What is the equation of the tangent line that touches the circle x squared plus 10x plus y squared -2y -39 equals 0 at the point of 3 2 on the Cartesian plane showing work?
First find the slope of the circle's radius as follows:- Equation of circle: x^2 +10x +y^2 -2y -39 = 0 Completing the squares: (x+5)^2 + (y-1)^2 -25 -1 -39 = 0 So: (x+5)^2 +(y-1)^2 = 65 Centre of circle: (-5, 1) and point of contact (3, 2) Slope of radius: (1-2)/(-5-3) = 1/8 which is perpendicular to the tangent line Slope of tangent line: -8 Tangent equation: y-2 = -8(x-3) => y = -8x+26 Tangent equation in its general form: 8x+y-26 = 0
Line intersecting a circle in two points?
A line can be tangent to a circle in which case it intersects it in one point, it can intersect it in two points, or no points at all. So the choices are 0,1 or 2.
Can a circle pass through three points of a straight line?
No, a circle can never pass through three points of a straight line. The circle will touch 1) no points of the line, 2) one point of the line (which is now tangent to the circle), or 3) two points of the line. A line can contain (at most) twopoints that lie on the line.
If a straight line intersects with a curve how many points do they have in common?
It depends what kind of curve you're talking about. if it's a circle, and the line is tangent to the circle, then one. If it's a circle, and the line is not tangent to the circle, then two. But if it's a goofy shaped curve then it could be any number. But the most likely answer to your question is 2.
If a circle of radius 2 is externally tangent to a circle of radius 8 what is the length of their common tangent?
the length of thr direct common tangent will be 2*{1/2 power of (r1*r2)} the answer will be 8 units in this case...
What are the tangent equations to the circle x2 plus y2 -6x plus 4y plus 5 equals 0 at the points where they meet the x axis?
Equation of circle: x^2 +y^2 -6x +4y +5 = 0 Completing the squares (x -3)^2 +(y +2)^2 = 8 Centre of circle: (3, -2) Radius of circle: square root of 8 Points of contact are at: (1, 0) and (5, 0) where the radii touches the x axis Slope of 1st tangent line: 1 Slope of 2nd tangent line: -1 Equation of 1st tangent: y -0 = 1(x -1) => y = x -1 Equation of 2nd tangent: y -0 = -1(x -5) => y = -x +5
Equal to 57.2958 degrees?
180/pi=57.2958 or two lines intersect in one point. that point is the center of a circle. if the angle between the two lines is 180/pi (57.2958...) then the radius of the circle is equal to the length of the section of circumference between the points where the 2 lines intersect the circle. This is true whatever the radius of the circle is.
How do you construct a tangent to a given circle and parallel to a given line?
There may be an easier way, but this is one way to do it: 1) establish the centerpoint of the given circle. - pick two random points on the circle and draw intersecting arcs A1 A2 of equal radius centered on those points. Then draw a line through the two points where A1 and A2 intersect. This line will pass through the circle center. - repeat with two other points. You now have two lines that intersect at the circle centerpoint C. 2) draw a line perpendicular to the given line that passes through C. - draw an arc centered on C that intersects the given line twice. Repeat the bisecting procedure as before using those two intersection points. Call the newly created line L. 3) draw the desired tangent line. - call the point where L intersects the given circle P. (Note that there are actually two such points, since there are two solutions to your problem - one on the near side and one on the far side.) Generate two equidistant points on L by drawing a small circle centered on P. Use those new points for the old bisection procedure and you have your answer!
What are the number of points at which 2 parallel lines intersect?
Zero; parallel lines never intersect.
How can you prove that the line between to points is a tangent of the smaller circle?
Step I: Show that both points are outside the smaller circles. Possibly by showing that distance from each point to the centre of the circle is greater than its radius. Step 2: Show that the line between the two points touches the circle at exactly one point. This would be by simultaneous solution of the equations of the line and the circle.
What are the equations of the tangents to the circle x2 plus y2 -6x plus 4y plus 5 equals 0 at the points where they meet the x axis on the Cartesian plane?
Circle equation: x^2 +y^2 -6x +4y +5 = 0 Completing the squares: (x-3)^2 +(y+2)^2 = 8 Center of circle: (3, -2) Radius of circle: square root of 8 The radius of the circle will touch the points of (1, 0) and (5, 0) on the x axis The tangent slope at (1, 0) is 1 The tangent slope at (5, 0) is -1 Equations of the tangents are: y = x-1 and y = -x+5
Do 2 planes intersect infinitely many points?
They need not intersect at all, but if they do, it will be along a straight line and so comprise infinitely many points.
What is the meaning of congruent circle?
2 circles that intersect each other
