No.
The reaction between silver and barium typically forms silver nitrate and barium nitrate. Silver and barium are both metals and can undergo a single displacement reaction where the more reactive metal, in this case, silver, displaces the less reactive metal, barium, in the compound.
The chemical equation for the reaction between barium and selenium is: Ba + Se → BaSe. This reaction forms barium selenide.
This reaction is:Ba(ClO3)2 = BaCl2 + O2
The reaction between barium (Ba) and phosphorus (P) would form barium phosphide (Ba3P2) as the product.
The reaction between chlorine and barium is called a single displacement reaction, where the chlorine displaces the barium in barium chloride to form barium chloride and elemental chlorine. The balanced equation for this reaction is: Cl2 + Ba → BaCl2 + Cl2
The spectator ions are Ag+ and (NO3)-.
The reaction between barium nitrate and aluminum produces aluminum oxide, barium oxide, and nitrogen gas. This is a redox reaction where aluminum displaces barium from its nitrate compound.
No. A substance will not react with itself.
The reaction between ammonium phosphate and barium hydroxide will produce barium phosphate and ammonium hydroxide as products. This is a double displacement reaction where the cations and anions switch partners. The balanced chemical equation for this reaction is: (NH4)3PO4 + 3Ba(OH)2 → Ba3(PO4)2 + 6NH4OH.
To balance the reaction between silver and barium, you first need to determine the chemical formulas of their compounds. Silver forms Ag+ ions while barium forms Ba2+ ions. When they react, they form silver nitrate (AgNO3) and barium chloride (BaCl2). The balanced equation is 2AgNO3 + BaCl2 -> 2AgCl + Ba(NO3)2. This is a double displacement reaction.
The balanced chemical equation for this reaction is: 2HCl(aq) + Ba(OH)2(aq) → BaCl2(aq) + 2H2O(l). This is a double displacement reaction where barium hydroxide reacts with hydrochloric acid to form barium chloride and water.
The spectator ions in the reaction between silver sulfate and barium nitrate are nitrate (NO3-) ions and sulfate (SO4^2-) ions. These ions do not participate in the formation of the precipitate (barium sulfate) and remain unchanged throughout the reaction.