For the individual resistor, the current is constant, regardless of any other resister that's attached to it in parallel. The current that results from all the resistors combined decreases as the resistance of one or more of the resistors increases.
It depends on where the resistor is added.
If it is placed across the load, the current increases.
If it is placed in series with the load the current is reduced.
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
This is a direct consequence of Ohms Law. Since each new resistor connected in parallel will allow more current to flow, the resistance of the circuit must be lower. R = E/I. Since I (current) has increased, and the voltage E is still the same, it follows that R (resistance) must be smaller. That's the way Ohms Law works.
As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
The total current in the circuit will decrease.
Just as the name of the component implies, electrical current gets resisted and therefore it diminishes unless an equally, larger voltage difference in that section of the circuit is applied. V=IR Current is inversely proportional to Resistance (when one goes UP, the other goes DOWN) Voltage is directly proportional to Resistance
I don't know which one it is a,,,bypass,,,,current loop,,,,shunt,,,wire resistor
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
vinegar is added to the beaker of baking soda and water. if the reaction is exothermic, what will happen?
An ohmmeter works by sending a DC voltage through the load under test and measuring the current passed. This works from Ohm's law E/R=I, so, for example, a meter with a source E=9v measuring a 10kΩ resistor would sense 0.0009 Amps (or 900µa) passing through the resistor. If there is some other current being passed through the resistor at the same time, there is no way for the meter to accurately account for this current which would be added to (or subtracted from) the sense current supplied by the meter. (This is an oversimplification since the Ohmmeter will actually provide a current-limited voltage source and must account for the series resistance of the meter (in the case of an analog electro-magnetic meter), current-limiting circuit, internal resistance in the meter batteries (if applicable), etc. in order to generate an accurate reading, however, the above describes the general theory of operation).
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
total resistance is each resistor added together
If the bulbs are in a series circuit the voltage drops at each bulb drops as additional bulbs are added. In a parallel circuit the voltage is constant no matter how many bulbs are added.