While the formation of a hemiacetal from an aldehyde and an alcohol ketone functional group by converting it temporarily into a cyclic ketal.
Hemiacetal
I think :Hemiacetal = aldehyde+ alcoholHemiketal = keton+ alcohol
Lactose is a disaccharide that consists of a galactose unit and a glucose unit bonded together with a β glycosidic linkage. The glucose unit can exists in one of two isomeric hemiacetal forms as well as in a free aldehyde form. The isomeric hemiacetal forms, beta and alpha lactose, are anomers because the hemiacetal hydroxyl group gives diasteromeric products at the anomeric carbon. Alpha and beta-lactose are able to change back and forth because of mutarotation, which is the change in specific rotation. The rate of this interchanging is influenced by a number of conditions including: the concentration of lactose, the temperature and the acidity, or pH, of the milk. At room temperature, the ratio of isomers is about 40% alpha to 60% beta. The solubility of the two anomers is temperature dependent and therefore the equilibrium concentration of the 2 forms will be different at different temperatures. At room temperature (70°F, 20°C) the equilibrium ratio is approximately 37% α- and 63% ß-lactose. At temperatures above 200°F (93.5°C) the ß-anomer is less soluble so there is a higher ratio of α- to ß-lactose. The type of anomer present does not affect the nutritional properties of lactose.
no
It is written like this R-CH(OR)-OH
Yes, every subgroup of a cyclic group is cyclic because every subgroup is a group.
Meiosis is not cyclic; rather it is a linear process. It does not cycle.
required to excite the electrons of the chlorophyll and start the cyclic and non-cyclic phosphorylation?
Acetal formation is a characteristic of a cyclic sugar. and acetal is formed when a hemiacetals react with an alcohol. If this hemiacetal group is sugar( glucose) and react with an alcohol to form an acetal ,it is known as glycoside. the other compound may or may not be monosaccharide.so in its cycle form it can not form acetal due to instability in configuration .
Due to absence of free hemiacetal group
LACTOSE sugar