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Does escape velocity depend upon height from which it is projected?
Wiki User
∙ 10y ago
Yes, it would. That's one reason why some artificial satellites were tossed into
orbit after being carried up aboard the space shuttle.
The reason is because escape velocity from Earth depends on Earth's gravity,
which in turn depends on the distance from the Earth's center. The higher you
go, the farther you are from the center of the planet, the less gravitational
force there is between you and the Earth, and the smaller the escape velocity
thus becomes.
Wiki User
∙ 10y ago
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What height will it gain after the escape velocity becomes half?
That will depend not only on the escape velocity, but also - very importantly - on the object's speed.
Derive a formula in term of acceleration due to gravity and radius for the Earth escape velocity?
m= mass of object v= velocity R= radius of the earth h= height from the surface to the escape velocity (mv2 ) ______ = G MEM R + h _____ (R+h)2 v2 =GME ______ (R +h)2 Ve = (√gR2 /(R+h)2 )
How do you calculate tak-off velocity of airplane?
peak height = (take off velocity^2)/(2*gravity)
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
A ball of mass m rolls off a cliff of height h with a horizontal velocity v it reaches the ground with vertical speed of?
If one assumes air resistance to be negligible, then: final velocity = sqrt( g * 2 * h ) where g is 9.8 metres per second per second. The quantities v and m do not matter, because gravitational acceleration does not depend on mass (all objects fall at the same rate) and because the horizontal velocity is independent of the vertical velocity.
What height will it gain after the escape velocity becomes half?
That will depend not only on the escape velocity, but also - very importantly - on the object's speed.
An object projected up with initial velocity v attains a height h Another object projected up with initial velocity 2v will attain what height?
4h
Answer for question of class XI kerala syllabus?
body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range
Derive a formula in term of acceleration due to gravity and radius for the Earth escape velocity?
m= mass of object v= velocity R= radius of the earth h= height from the surface to the escape velocity (mv2 ) ______ = G MEM R + h _____ (R+h)2 v2 =GME ______ (R +h)2 Ve = (√gR2 /(R+h)2 )
What angle a body is projected to get maximam height?
45 degrees
Does hang time depend on your vertical component of velocity when you jump?
The higher you jump the longer your hang time. Your height is dependant on the force applied to the ground at liftoff
What is height measured in?
it can be. if you wanted to.
How can rockets escape from gravity?
Escape velocity is defined to be the minimum velocity an object must have in order to escape the gravitational field of the earth, that is, escape the earth without ever falling back. From the surface of the Earth, escape velocity (ignoring air friction) is about 7 miles per second, (11.2 km/sec) or about 25,000 miles per hour. Given that initial speed, an object needs no additional force applied to completely escape Earth's gravity. More can be seen about this in the related link below.
How do you calculate the height of the average velocities?
It isn't clear what you mean by the "height of a velocity".
How do you measure velocity of a falling object if height is 2m?
Velocity= sqrt(2(distance*gravity))
How do you find final velocity given height and mass?
the final velocity assuming that the mass is falling and that air resistance can be ignored but it is acceleration not mass that is important (can be gravity) final velocity is = ( (starting velocity)2 x 2 x acceleration x height )0.5
How do you calculate height based on velocity and time?
I assume you refer to the formula distance = velocity x time. If an object moves upward, the distance would become the height.
