When Fr is oxidised, it does so by donating electrons to the oxidant (eg. Oxygen, H+ )
Francium gives away electrons very easily due to its location in the alkali metal group, which makes its outer electron very loosely bound. This makes Francium highly reactive and likely to form ions by losing its single valence electron.
An acid is defined as a proton donor, which means it gives it's electrons away An acid is defined as a proton donor, which means it gives it's electrons away
Oh, dude, when elements react, they give away or take electrons to achieve a stable configuration. It's like a high-stakes game of electron trading - one element might be like, "Here, take my electron, I don't need it," while another is all, "Thanks, I'll add this to my collection." So yeah, electrons are the hot commodity in the world of chemical reactions.
it gives two of its electrons away.
The iron will not react unless you react it with calcium chloride. This is because Chloride is very electronegative (it has a high affinity for electrons) Both iron and calcium are not very electronegative and would like to give away their electrons. The Chloride ion accepts these electrons to get a full valent shell.
Francium is located on the bottom left side of the periodic table of elements. Meaning it has the largest number of electron shells and lowest electron negativity. Thus having the biggest atomic size.
Yes, sulfur can give away electrons when forming ionic bonds with elements that have a greater tendency to attract electrons. For example, in the compound sodium sulfide (Na2S), sulfur gives away electrons to sodium to form an ionic bond.
It's important to note that plutonium and uranium (element names are not normally capitalized in the middle of a sentence) have isotopes which are stable enough that their reactivity is experimentally known, while the most stable isotope of francium has a half-life of about 20 minutes. Francium's reactivity is therefore partially a matter of conjecture... the energy given off by its radioactive decay would literally vaporize any reasonably sized piece. That said, as an alkali metal francium would be much more reactive than uranium or plutonium, both of which are transition metals.
When going through an ionic bond, boron gives away three electrons.
It gives away electrons.
When an atom gives away electrons to another atom, it becomes positively charged (as it loses negatively charged electrons) and forms a positively charged ion. The atom that gains electrons becomes negatively charged and forms a negatively charged ion. This transfer of electrons results in the formation of an ionic bond between the two atoms.
Sodium gives away one electron to achieve a stable electron configuration, forming a cation with a +1 charge.