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IPod touch 5g Coming with Aluminum Body and 4-Inch Display?
New iPod Touch 5G Coming with with 4-Inch Display, Aluminum Body. If want to know more I m leaving link in source
What is the cost m cm at p metre?
To find the cost of ( m ) centimeters at a price of ( p ) per meter, first convert centimeters to meters by noting that ( 1 ) meter equals ( 100 ) centimeters. Thus, ( m ) centimeters is equal to ( \frac{m}{100} ) meters. The cost can then be calculated as ( \text{Cost} = \frac{m}{100} \times p ). Therefore, the total cost is ( \frac{m \cdot p}{100} ).
Can you syn mini episodes like ncis to a ipod touch?
Some episodes you can download off youtube for free (using a youtube downloader) and they will be converted to M-PEG (iPod movie) so you can add them to your ipod. I don't think you can copy episodes from bought dvds though :(
Is the iPod Touch good?
nah ipod touchs are not good at all!! dont waste your time buying one!! they suck!! Yours sincerely Jesse M joey handy say dont believe jesse m its verry good i know becouse my cousiin feliuasa handy has one and its verry good sined joeyhandy
Can you call or text on the i pod touch?
yes. you can. you can also send and reseve text messages. go to the app store, search "txt now" then pick the app you want the most. with the calling app, go to the app store and search "calling" or "phone" pic the app you want. NOTICE: the calling app will not work if your ipod does not have a built in mic, or a plug in mic.
Distances of all he planets from sun in standard exponential form?
The average distances of the planets from the Sun, expressed in astronomical units (AU) and standard exponential form, are approximately as follows: Mercury: (0.39 , \text{AU} ) or (3.9 \times 10^{10} , \text{m}), Venus: (0.72 , \text{AU} ) or (1.1 \times 10^{11} , \text{m}), Earth: (1.00 , \text{AU} ) or (1.5 \times 10^{11} , \text{m}), Mars: (1.52 , \text{AU} ) or (2.3 \times 10^{11} , \text{m}), Jupiter: (5.20 , \text{AU} ) or (7.8 \times 10^{11} , \text{m}), Saturn: (9.58 , \text{AU} ) or (1.4 \times 10^{12} , \text{m}), Uranus: (19.22 , \text{AU} ) or (2.9 \times 10^{12} , \text{m}), and Neptune: (30.07 , \text{AU} ) or (4.5 \times 10^{12} , \text{m}).
If a rectangular field measures 6.0 m by 8.0 m what is the area of the field in square centimeters (cm2)?
To find the area of the rectangular field, multiply the length by the width. The area is (6.0 , \text{m} \times 8.0 , \text{m} = 48.0 , \text{m}^2). Since 1 square meter equals 10,000 square centimeters, the area in square centimeters is (48.0 , \text{m}^2 \times 10,000 , \text{cm}^2/\text{m}^2 = 480,000 , \text{cm}^2). Thus, the area of the field is 480,000 cm².
What rate of a reaction that follows the rate law rate kAmBn where k 1.5 A 1 M B 3 M m 2 n 1?
To determine the rate of the reaction using the rate law ( \text{rate} = k[A]^m[B]^n ), we can substitute the values given. With ( k = 1.5 , \text{M}^{-2}\text{s}^{-1} ), ( [A] = 1 , \text{M} ), ( [B] = 3 , \text{M} ), ( m = 2 ), and ( n = 1 ), the rate can be calculated as follows: [ \text{rate} = 1.5 \times (1)^2 \times (3)^1 = 1.5 \times 1 \times 3 = 4.5 , \text{M/s} ] Thus, the rate of the reaction is ( 4.5 , \text{M/s} ).
If A car goes from 16 ms to 2 ms in 3.5s what is the cars acceleration?
To calculate the car's acceleration, use the formula ( a = \frac{{v_f - v_i}}{{t}} ), where ( v_f ) is the final velocity, ( v_i ) is the initial velocity, and ( t ) is the time. Here, ( v_f = 2 , \text{m/s} ), ( v_i = 16 , \text{m/s} ), and ( t = 3.5 , \text{s} ). Plugging in the values: [ a = \frac{{2 , \text{m/s} - 16 , \text{m/s}}}{{3.5 , \text{s}}} = \frac{{-14 , \text{m/s}}}{{3.5 , \text{s}}} \approx -4 , \text{m/s}^2. ] Thus, the car's acceleration is approximately (-4 , \text{m/s}^2).
A bookcase has a base 1m long and 0.5m wide It has a mass of 300kgFind the pressure it exerts on the floor in kPa?
To find the pressure exerted by the bookcase on the floor, use the formula for pressure: ( \text{Pressure} = \frac{\text{Force}}{\text{Area}} ). The force is equal to the weight of the bookcase, which is its mass multiplied by the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )). The area of the base is ( 1 , \text{m} \times 0.5 , \text{m} = 0.5 , \text{m}^2 ). Calculating the force: ( 300 , \text{kg} \times 9.81 , \text{m/s}^2 = 2943 , \text{N} ). Then, the pressure is ( \frac{2943 , \text{N}}{0.5 , \text{m}^2} = 5886 , \text{Pa} ) or ( 5.886 , \text{kPa} ).
How many liters would you need to get 0.5moles if you had 0.1m solution?
To find out how many liters of a 0.1 M solution are needed to obtain 0.5 moles, you can use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ] Rearranging this gives: [ \text{liters of solution} = \frac{\text{moles of solute}}{\text{Molarity (M)}} ] Substituting in the values: [ \text{liters of solution} = \frac{0.5 \text{ moles}}{0.1 \text{ M}} = 5 \text{ liters} ] Therefore, you would need 5 liters of a 0.1 M solution to obtain 0.5 moles.
What is the molarity of 449 ml of solution containing 183 mmol of glucose?
To find the molarity (M) of the solution, use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ] First, convert 183 mmol to moles: [ 183 , \text{mmol} = 0.183 , \text{mol} ] Next, convert 449 ml to liters: [ 449 , \text{ml} = 0.449 , \text{L} ] Now, calculate the molarity: [ \text{M} = \frac{0.183 , \text{mol}}{0.449 , \text{L}} \approx 0.408 , \text{M} ] Thus, the molarity of the solution is approximately 0.408 M.
