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Does it matter which dimensions you select for the length and width when you find the area of a rectangle?
Wiki User
∙ 12y ago
not really
but the length is always the longer side :)
Wiki User
∙ 12y ago
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Does it matter which dimensions you select for length and width when you find the area of a rectangle?
No. Because of the commutative law of multiplication, it makes no difference.
What rectangle has a perimeter 16 units?
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
How can you get a rectangle with whole number side length's and a perimeter of 26 meters?
Select any two whole numbers that sum to half of 26 = 13.
How do you divide a rectangle by 5 equal parts?
Select any one side and divide its length into 5 equal parts. Draw lines that are parallel to the adjacent side to the opposite side. This will divide the rectangle into 5 equal strips.
How do you draw a 12 perimeter rectangle?
Select any number, B, less than or equal to 3 units. Let L = 6 - B units. Then, a rectangle with length L and breadth B will have a perimeter of 12 units.
How do you find the perimeter of a rectangle when given area?
You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.
You can select the cable length in the option box.?
You can select the cable length in the option box.
Finding the length of a rectangle without knowing the area or width?
If you don't know the width, area or length, you would have to have several other measurements that would permit you to calculate the width or length. A rectangle's main formula is l x w x h (length times width x height). If you don't have two of them, finding the third one is complicated, but doable under some select circumstances. If you had the lengths of two sides of a triangle with two vertices matching two of the rectangle's vertices, you could use trigonometry find the length of the shared side. If this shared side was the length then you would be golden. Or you could measure.
Does it matter what to factors you select to complete a factor tree?
Yes, but it doesn't matter what two factors you select to start one.
Does it matter what two factors you select to completes a factor three?
Yes, but it doesn't matter what two you select to start one.
Does it matter what two factors you select to completea factor tree?
It doesn't matter what you select to start, but all the factors must be prime at the completion.
Difference between qualifying and determining dimensions?
To select the important segmenting dimensions, think about two different typesof dimensions. Qualifying dimensions are those relevant to including a customertype in a product-market. Determining dimensions are those that actually affect thecustomer's purchase of a specific product or brand in a product-market.
