Mendelevium can make ionic bonds.
The bond is covalent.
BOTH
No. Sodium and Chlorine form an Ionic bond because the difference of their electronegativities equal 2.1. Use this: Nonpolar-covalent bond - 0-0.39 Polar-covalent bond - 0.4-1.79 Ionic bond - 1.8+
False. Sharing valence electrons to make a bond creates a covalent bond, not an ionic bond.
H and Cl will form a polar covalent bond when they combine. This is because hydrogen has a slight positive charge and chlorine has a slight negative charge, leading to a sharing of electrons in a covalent bond rather than a transfer of electrons in an ionic bond.
The presence of Na (Sodium, a metal) and HCO (non metals) make it a bond between a metal and non-metals, thus it is ionic bond.
To correct the sentence, you can say: "A covalent bond is the sharing of electrons between atoms in a molecule, whereas the force of attraction between oppositely charged ions in an ionic compound is called an ionic bond."
Not at all, in a covalent bond there is no losing or gaing of electrons as both of the atom reacting to make a covalent bond needs electrong therefore they share the electrons to stablized, but in ionic compound like NaCl, there is a losing of electron and gaining of electrons, therefore one element loses and one element gains. Ionic bond or "electrovalent bond" are strong bonds as compare to covalent bonds.
No, calcium and sulfur do not typically form a covalent bond because calcium typically forms ionic bonds by donating its two valence electrons to sulfur, which is a nonmetal. Calcium and sulfur would form an ionic bond in a compound like calcium sulfide (CaS).
No, hydrogen and oxygen do not form an ionic bond. They typically form a covalent bond when they combine to make water (H2O). In this bond, they share electrons instead of transferring them.
Fluorine atoms have a covalent bond between each other to form a covalent molecule. Fluorine bonded to a metal will have ionic bonds. Fluorine bonded to a non-meatl will have polar covalent bonding.
It is in a Ionic bond.