There are 5 chiral carbon atoms in norethynodred.
For a molecule with n chiral centers, there are a possible 2^n isomers that can be formed.
For a molecule with n chiral centers, there are a possible 2^n isomers that can be formed.
The number of chiral center of tetracycline is 5 .. there are 5 chiral carbons.If there is confusion about the 25=32 Remark, the previous writer was using the equation- 2 to the power of n= then the number of possible stereoisomers, where n is the number of stereogenic centers, hence 2 to the power of 5 is 32.
There is only 1 center - 1 chiral carbon and hence two optically active isomers.
No it doesnt have any....
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There are 5 chiral carbon atoms in norethynodred.
I think glucose has 4 chiral centres four carbon atoms has four different compound/elements bonded to it.
fifteen.
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For a molecule with n chiral centers, there are a possible 2^n isomers that can be formed.
This is my understanding.... though I am no expert by any means... Aldopentoses have 3 chiral centers (assymetrical carbon atoms) which allows for 8 stereoisomers (4D and 4L) while ketopentoses have 2 chiral centers which makes 4 stereoisomers .
For a molecule with n chiral centers, there are a possible 2^n isomers that can be formed.
Psicose has four chiral carbon atoms, so it has four chirality centers.
The 8 isomers of pentose are in the carbohydrate family and are characterized as simple sugars, or monosaccharide's. The asymmetric chiral centers generally refer to the presence of interaction with polarized light.