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Answered 2011-08-21 12:49:42

No. as rust is caused by the oxidation process of:

O2+2H2O+4e = 4OH

in sodium hydroxide the hydroxide is already present making it harder to form and therefore making rust harder to form. Sodium hydroxide is a rust inhibitor.

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iron chloride + sodium hydroxide = sodium chloride +iron hydroxide

Iron Sulphate + Sodium Hydroxide -> Sodium Sulphate (Na2SO4) and Iron Hydroxide (Fe(OH)2)

Metallic sodium is far more chemically active than iron is. Iron rusts, but sodium reacts rapidly with water to form sodium hydroxide and hydrogen gas.

Iron is an element; rust is a compound of iron, hydroxide and oxygen.

iron (II) sulfate and sodium hydroxide form a double displacement reaction with a precipitate. The products are Iron (II) hydroxide (s) and sodium sulfate (aq)

No, the iron reacts with oxygen to create iron oxide (rust).

You get Iron (III) Hydroxide and Sodium Nitrate. It is a double displacement chemical reaction...

NO! It reacts with air to form iron oxide (AKA rust) and water to form iron hydroxide (AKA rust)

Rust is also called oxidized iron. Also dehydrated iron hydroxide: Fe2O3.nH2O

Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]

The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.

Sodium displaces the sulfate to make sodium sulfate; iron displaces the hydroxide to make ferrous hydroxide which becomes brown.

It wont rust! it may be due to its basic state but i am unsure as of why!

No - essentially iron rust [Fe2O3] is defined as the oxidized derivative of the metal Iron [Fe] However, if the iron rust is not properly prepared we may get contamination. These include Iron Hydroxide, Iron, etc. Hope this helps - bwabwa

Iron (II) chloride and sodium hydroxide react to produce iron (II) hydroxide and sodium chloride. FeCl2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaCl(aq) This is a double replacement/displacement reaction.

Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).

No, it is hardly soluble in sodium hydroxide though it is amphoteric. It's better in (hydrochloric) acid.

Rust consists of hydrated iron oxides Fe2O3·nH2O and iron oxide-hydroxide (FeO(OH), Fe(OH)3).

The reaction is: 2NaOH + FeCl2 = 2NaCl + Fe(OH)2 Iron hydroxide is a precipitate.

It produces a reddish precipitate of Iron(III) hydroxide and Sodium sulfate: Fe2(SO4)3 + NaOH ----> Fe(OH)3 + Na2SO4

Iron. Rust is called Iron oxide and has the chemical formulae of Fe2O3·nH2O and for iron(III) oxide-hydroxide: FeO(OH)·Fe(OH)3.

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