No. as rust is caused by the oxidation process of:
O2+2H2O+4e = 4OH
in sodium hydroxide the hydroxide is already present making it harder to form and therefore making rust harder to form. Sodium hydroxide is a rust inhibitor.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
When iron (III) nitrate reacts with sodium hydroxide, it forms iron (III) hydroxide and sodium nitrate. The balanced chemical equation for this reaction is: Fe(NO3)3 + 3NaOH → Fe(OH)3 + 3NaNO3. Iron (III) hydroxide is a brown solid that forms as a precipitate in this reaction.
The dark green precipitate formed when sodium hydroxide is added to iron II compounds is iron II hydroxide. When left standing, the iron II hydroxide undergoes further oxidation to form iron III hydroxide, which is orange-brown in color. This change in color is due to the conversion of iron II to iron III within the precipitate.
No, it is hardly soluble in sodium hydroxide though it is amphoteric. It's better in (hydrochloric) acid.
When sodium hydroxide solution is added to a rusty nail, it reacts with the iron oxide (rust) to form soluble sodium ferrate, which helps to dissolve and remove the rust from the surface of the nail. This process is known as chemical dissolution, where the sodium hydroxide breaks down the rust into a soluble form that can be easily washed away.
Yes, it tarnishes after coming in contact with the air because it gradually reacts with oxygen in the air to produce sodium peroxide and sodium oxide. When exposed to water, it produces sodium hydroxide (lye) and flammable hydrogen gas.
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
= iron hydroxide plus sodium chloride
The products of the reaction between sodium hydroxide and iron(III) sulfate are iron(III) hydroxide and sodium sulfate. This reaction forms a precipitate of iron(III) hydroxide while sodium sulfate remains in solution.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
No, calcium hydroxide does not cause rust. Rust is a specific type of corrosion that occurs on iron and its alloys, while calcium hydroxide is a chemical compound that does not react with iron in a way that causes rusting.
The reaction between iron (III) chloride and sodium hydroxide is a chemical change as new substances are formed. Iron (III) hydroxide and sodium chloride are produced as a result of the reaction.
When iron (III) nitrate reacts with sodium hydroxide, it forms iron (III) hydroxide and sodium nitrate. The balanced chemical equation for this reaction is: Fe(NO3)3 + 3NaOH → Fe(OH)3 + 3NaNO3. Iron (III) hydroxide is a brown solid that forms as a precipitate in this reaction.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
NO! It reacts with air to form iron oxide (AKA rust) and water to form iron hydroxide (AKA rust)