If r is the distance from the sound source the sound intensity drops with (1/r)².
intensity
- 6 dB is incorrect. It will decrease by 12 dB.
The intensity increases by a factor of 4-APEX
The intensity of a sound produced by a point source decreases as the square of the distance from the source. Consider a riveter as a point source of sound and assume that the intensities listed in Table 12.1 are measured at a distance 1 m away from the source. What is the maximum distance at which the riveter is still audible? (Neglect losses due to energy absorption in the air.)
The redshift is caused by relative motion that increases the distance from the source to the observer. The faster the source of light is moving away to the observer, the greater the redshift
The intensity of light from most light sources is inversely proportional to the square of the distance from the source. So the intensity two meters from an incandescent lamp is one quarter of the intensity at one meter, and at three meters from the lamp the intensity is one ninth of the intensity at one meter. Laser light ideally has the same intensity at any distance.
- 6 dB is incorrect. It will decrease by 12 dB.
The intensity increases by a factor of 4-APEX
The intensity of a sound will decrease according to an inverse square law.
Intensity is defined as energy per unit area. As we move away from the point source, the area over which the energy distributes is generally spherical or hemispherical. The area of a sphere or hemisphere increases proportional to the square of radius, where the radius in this case is the distance from the point source. Thus Intensity, which is inversely proportional to area, decreases with the square of distance. Hope it was clear. Visit MechMinds.ca for any further help!
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
intensity increases as distance decreases. you cant explain that. scources- bill o'reily
Light intensity is inversely proportional to the square of the distance: I = k/d2
Intensity
The intensity reduces in proportion to the square of your distance from the source.
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
physics
It's an inverse-square law - for instance, double the distance, and the intensity will be reduced by a factor 1/4.This assumes that there is nothing absorbing the light (for instance, fog); if there is, the intensity in the above example will of course be even less than 1/4 the original intensity.