A capacitor charge as a time constant of R resistance C capacitance in ufd and it is defined as 63% for one time constant for the constant voltage source. Electronic engineers assume that a capacitor is fully charged by a 5 times constant. however mathematically speaking it will never be fully charged for obvious reasons. Therefore the answer is current will never stop/
There is a transient current flow when the capacitor is first connected to the DC souirce. This transient lasts about five time constants (RC time). Then the capacitor is mostly charged and the transient flow stops and there is no current flow thereafter.
in a series RC circuit phase angle is directly proportional to the capacitance
increase.
Current stops flowing.
A capacitor resists a change in voltage. Initially, a capacitor given a DC voltage will appear to have very low resistance, but as current flows and time goes by, the resistance will increase as the voltage approaches the applied voltage. At equilibrium, the voltage across the capacitor will be equal to the applied voltage, the current will be zero, and the resistance will be infinity.
-- In a series circuit, no matter where you install the ammeter, it will always read the same current. -- In a parallel circuit, the ammeter may read a different current when it's moved to a different parallel branch.
large capacitors will become charged in a fraction of a second if a DC voltage is applied to its terminalsonce a capacitor becomes fully charge it acts as an open circuit to direct current in other words, once the capacitor charged by a DC voltage, the current will cease to flow in the branch of the circuit which contains the capacitor.a capacitor also offers opposition known as (capacitive reactance) to alternating current. it does not , however ,act as an open circuit to when an a-c alternating current voltage is applied.
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
If the capacitor is charged then the battery will explode.
It will increase the ripple factor that the capacitor is in the circuit to smooth out.
It flows out of the capacitor into the external circuit
series resonant circuit
When the terminals of a capacitor are connected together, the capacitor will discharge, returning to a zero potential state. Capacitors resist voltage change, meaning that if the capacitor is in a circuit that has zero voltage potential, the capacitor will eventually achieve zero potential. If the capacitor is in a circuit that has a 5 volt potential, the capacitor will seek and attempt to maintain that 5 volt potential (provided that the capacitor is rated at 5 volts or more). In an AC circuit, the capacitor will tend to smooth out the sin wave of the current, resisting change in both directions. In a DC power supply circuit, a capacitor will tend to reduce the voltage "ripple", and if the circuit is designed properly, will provide a smooth DC voltage. Shorting the terminals of a capacitor is effectively what often happens in many circuits; it's not a problem.
Current may go to the ground, or another conductor. Also, your body may act as a capacitor, in other words, absorbing some current even if the circuit is not complete. Note that the normal household current is AC.
Current through that part of the circuit will stop.
in a series RC circuit phase angle is directly proportional to the capacitance
Nothing will happen to circuit..... as usual the circuit would be supplying 220v(if india) and certain current...but there is no bulb to consume power...
Closing a switch in an electrical circuit will complete the circuit. The supply voltage will then be applied to that circuit, and current will flow through that circuit.