Yes, as long as the holster you have will fit a P226R (newer model w/ picatinny rail). The difference between the P226R (standard) and P226R combat is that the combat has an alloy frame, short reset trigger (resets in 1/8" inch for high speed shooting) and has the short trigger (which is MUCH nicer, esp. if you have small hands). The combat is available in dark earth and also has the option of the threaded barrel, IF you get the threaded barrel you just have to make sure your using a holster capable of handling a full 5" barrel instead of a 4.4" barrel as the threads add approx. 1/2" to the OAL. I'm not aware of any holsters that can handle a 4.4" barrel but not a 5", usually on holsters that are NOT gun specific they will handle "any large frame auto or revolver" and both lengths would be covered. Hope this helps!!!
It depends on the holster. Some holsters are marked for the 229 and 226, and some holsters that work for the 226 work for the 220. Some holsters are molded specifically for one one model and won't work, or won't work well for other models.
do you mean a 229 instead of a 228? my gun expert seems to think it would be the 226. these guns are used by the navy seals and Texas rangers. No, there is a P226 (full size model) and a P228 (compact) both are 9mm
Yes, anywhere from 150-400 is considered in the normal range.
226 x 1 = 226 226 x 2 = 452 226 x 3 = 678 226 x 4 = 904 226 x 5 = 1130 226 x 6 = 1356
113 x 2 is 226
The cube is raised to the power of 3, or 226 x 226 x 226 = 11543176.
226 2,113
78% of 226 days= 78% * 226= 0.78 * 226= 176.28 days
-226, -113, -2, -1, 1, 2, 113, and 226 are the factors of 226. Each factor can be multiplied by another integer to get the product of 226.
The factors of 226 are: 1, 2, 113, and 226.The prime factors of 226 are: 2 and 113.
226/2 = 113
226 / 2 = 113