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Bounce height will not depend on the ball's radius. It will however depend on the material of the ball and the speed at which it hits the ground
No, but as the rotation speed decreases, the maximum power loading in the spot decreases, so either the power must be turned down, or the spot made larger.
The centripetal acceleration is equal to velocity squared over radius. a=v^2/r
For circular motion, linear speed = angular speed (in radians) x radius. How the radius affects speed depends what assumptions you make about the problem. For example, if you assume the radius increases but the angular speed does not, then of course the linear speed will increase.
Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body
Bounce height will not depend on the ball's radius. It will however depend on the material of the ball and the speed at which it hits the ground
The centre of the circle does not turn at all: the axis of rotation goes through it.
You can calculate the centripetal ACCELERATION with one of these formulae: acceleration = velocity squared / radius acceleration = omega squared x radius Acceleration refers to the magnitude of the acceleration; the direction is towards the center. Omega is the angular speed, in radians per second. To get the centripetal FORCE, you can use Newton's Second Law. In other words, just multiply the acceleration by the mass.
In 2-dimensions, the formula for rotation through d degrees is [post-]multiplication by the matrix [cos(d) sin(d)] [-sin(d) cos(d)]
The relevant formula here is:centrifugal acceleration = omega squared x radiusomega (the angular speed) doesn't change in this formula (for the situation under consideration), but "radius", the distance from the axis of rotation, does.
No, but as the rotation speed decreases, the maximum power loading in the spot decreases, so either the power must be turned down, or the spot made larger.
The answer does not depend on which gear is driving. Linear-wise, the two gears are meshed so the teeth are moving at the same speed. Rotation-wise, the smaller gear has smaller radius so it is "turning faster" in terms of RPMs.
The centripetal acceleration is equal to velocity squared over radius. a=v^2/r
Depends on motor load transmission, rotation of motor speed, frequency.
For circular motion, linear speed = angular speed (in radians) x radius. How the radius affects speed depends what assumptions you make about the problem. For example, if you assume the radius increases but the angular speed does not, then of course the linear speed will increase.
The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.
The earth's orbital speed has no influence or effect on its rotation.