It depends by how much it changes. Power (watts) = current (amps) x voltage
If the current halves and the voltage doubles, the power won't change. But if the current is cut in half and the voltage only goes up by a little bit the watts will go down. If the current only goes down a little bit but the voltage doubles, then the watts will go up.
Wattage= current*voltage*power factor. Wattage=VI Cos(@)
Wire size is based of the amperage of the device. To answer this question the amperage is needed or the wattage and voltage of the device.
If the voltage in your vacuum is 120 then you divide the Wattage by the Voltage to get 3 amps.
It depends on the voltage; which depends on the country. If you know the voltage, divide the wattage by the voltage, the result is the amperage.
Most equate wattage with the amount of light a bulb will put out. But, the wattage is the result of the resistance of the element and the voltage and is the amount of heat. the frequency is unrelated.
That depends on the voltage V. Wattage P = amperage A times voltage V.
Wattage= current*voltage*power factor. Wattage=VI Cos(@)
wattage is nothing but power product of current and voltage p=v*i
Wattage, you mean power. Power = V * I. V - the voltage and I the current.
If running at 110V, that is 10Amps. Wattage = Voltage x Current Current = Wattage / Voltage - Neeraj Sharma
Wattage = Outage Voltage + Outage Wattage
Devide the wattage by the voltage
Wire size is based of the amperage of the device. To answer this question the amperage is needed or the wattage and voltage of the device.
wattage is voltage and amperage multiplied. example V/A=W or 120v x 20a=2400 watts
It depends on the voltage; which depends on the country. If you know the voltage, divide the wattage by the voltage, the result is the amperage.
Generally the lumen output of bulbs is proportional to the power used, if the bulbs are operated at their rated voltage.
Wattage is the product of amperage times voltage. There is not enough information to give an answer.