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CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O
LiC2H3O2 + H2O
CH3COOH + KOH = CH3COOK + H2O
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O
LiC2H3O2 + H2O
CH3COOH + KOH = CH3COOK + H2O
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
Acetic acid is weak acid.
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
HC2H3O2(aq) + KOH(aq) → KC2H3O2(aq) + H2O(l)...... I don't know about Net Ionic, but i think this is correct
2HC2H3O2 + Ca(OH)2 → H2O + Ca(C2H3O2)2Acetic acid + calcium hydroxide → water + calcium acetate
Glacial acetic acid reacts with sodium hydroxide to give sodium acetate and water CH3COOH + NaOH = CH3COONa + H2O
no.