NaOH+HCl gives NaCl and H2O. This is the balanced one
aniline is a base so forms salts with both acids. C6H5-NH2 + H2SO4 = C6H5-NH3+HSO4- and C6H5-NH2 + HCl = C6H5-NH3+ Cl-
The chemical reaction is:
C6H5NH2 + HCl = (C6NH3)Cl
the equation of aniline?
C6H5-NH-CH3 + HCl → (C6H5-NH2-CH3)+Cl-
(C2H5)3N + HCl = (C2H5)3N+Cl-
HCl + NaOH -----> NaCl + H2O
It will be a neutralization reaction and the products will be NaCl and H2O
This reaction gives ammonium chloride as the product.
-55.8 KJ/mol
(C2H5)3N + HCl = (C2H5)3N+Cl-
HCl + NaOH -----> NaCl + H2O
The equation involved is a neutralization reaction. HCl + NaOH -> NaCl + H2O In this reaction, acid and base react to produce a salt.
It will be a neutralization reaction and the products will be NaCl and H2O
This reaction gives ammonium chloride as the product.
NaOH(aq) + HCL(aq) = NaCl(aq)l + H2O(l)
The general word equation for salt formation by neutralization is acid + base.
-55.8 KJ/mol
Nats.
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
Phenoxide and Hydrochloric acid: C6H5O-Na+ + HCL ----> C6H5OH + NaCl
HCl + CuSO4