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NO2(g)+SO2(g)-->NO(g)+SO3(g) here NO2 act as a oxidising agent

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Q: Equation to show NO2 acts as a reducing agent and oxidising agent?
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Why is sulfur-dioxide reducing while tellurium-dioxide is oxidising agent?

S+O2->SO2 Oxidation no. of sulphur changes from 0 to +4. Due to presence of d-orbitals(vacant) sulphur can extend its covalency & show oxidation states till +6, which is stable in sulphur (eg: SF6). Hence it acts as a reducing agent. Te+O2->TeO2 Oxidation no. of Te changes from 0 to +4. Unlike sulphur Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Therefore there can only be a decrease in it oxidation state (it can decrease to -2, +2). Hence it acts as an oxidising agent.


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