A gold coin with a diameter of 1 centimeter and a 1 mm thickness has a volume of .07854 cubic centimeters. Gold has a density of 19.30 grams per cubic centimeter. There is 1.5158 grams of gold or 7.7 millimoles or 4.637 E21 atoms.
A gold coin with a diameter of 1 centimeter and a 1 mm thickness has a volume of .07854 cubic centimeters. Gold has a density of 19.30 grams per cubic centimeter. There is 1.5158 grams of gold or 7.7 millimoles or 4.637 E21 atoms.
Work out the volume of the coin first. Then using density formula, mass of this coin can be calculated. From mass find the number of moles. Then Avogadro's number will take care of the rest.
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We need to know the diameter of the wire to calculate the volume and the mass. Number of atoms is: 2,58.1023.r2, where r is the radius of the wire.
One Angstrom is defined as 10-10 centimeters. Therefore, the number of any units with a diameter of 2.2 Angstroms that would be required to span 1.0 cm is 1.0/10 -10 or 4.5 X 109 calcium atoms., to the justifiable number of significant digits.
there are 16 atoms in sulfur, because the number of atoms in an element is equal to its atomic number, which is the number at the top of the square which is bolded
The number of atoms is 54,2.10e23.
Yes: Alkenes follow the general formula: CnH2n (n being the number of carbon atoms in the chain), so in Alkenes, there will be twice as many H atoms than C atoms. Alkanes: CnH2n+2 Alkenes:CnH2n Alkynes:CnH2n-2
we dont find thickness of molecule we find the radius of it vander waal radius for gases. first of all we take a beaker (all dimension are known), then we inject molecules of substance but a uniform flow and with the use of atomizer these atoms or molecules settle down on the bottom of beaker layer by layer when we get full bottom covered with molecules then we find thickness of the layer and estimate no. of atoms in layer with the help of different methods and the we divide it with estimated no. of atoms this way we find the diameter of atoms or molecule then we just divide it by 2. more precisely scientist take extreme precautions while performing the above experiments.
We need to know the diameter of the wire to calculate the volume and the mass. Number of atoms is: 2,58.1023.r2, where r is the radius of the wire.
One Angstrom is defined as 10-10 centimeters. Therefore, the number of any units with a diameter of 2.2 Angstroms that would be required to span 1.0 cm is 1.0/10 -10 or 4.5 X 109 calcium atoms., to the justifiable number of significant digits.
Depending on the thickness of the foil.
Given an atom with diameter of 100 picometers, the diameter in inches is 4 nano inches.
The number of atoms in the universe is estimated at 1078 to 1082. So the number of molecules would be smaller than this, obviously. Reference: http://www.universetoday.com/36302/atoms-in-the-universe/
atoms
The definition of one mole is: It is a number (eg. of particles of any kind), like pi is a number (of ratio from diameter to circle).It is a very big number, symbolised as NA (and named after Avogadro):NA = 6.022 * 1023 (-/mol) or (mol-1)So there are 1.62 * NA = 9.76 * 1023 atoms in a mole(it is not important of what kind the atoms are).
100 million helium atoms, being the number (1.0E-2 m)/(100E-12 m).
As in number? No of atoms = avagadros number (6.02X10^23) times number of mole of atoms
None. A line is a 1-dimensional object and so has no thickness. An atom, no matter how small, has a finite thickness and so cannot be IN a line.
The diameter is lower now.