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Physics
Elements and Compounds
Atoms and Atomic Structure
Gold and Precious Metals

Estimate the number of gold atoms in a gold coin with the diameter of 1 cm and a thickness of 1 mm?


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Wiki User
2009-07-25 09:20:16
2009-07-25 09:20:16

Work out the volume of the coin first. Then using density formula, mass of this coin can be calculated. From mass find the number of moles. Then Avogadro's number will take care of the rest.

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A gold coin with a diameter of 1 centimeter and a 1 mm thickness has a volume of .07854 cubic centimeters. Gold has a density of 19.30 grams per cubic centimeter. There is 1.5158 grams of gold or 7.7 millimoles or 4.637 E21 atoms.

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the atom diameter ranges from hydrogen atoms to the largest atoms.

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we dont find thickness of molecule we find the radius of it vander waal radius for gases. first of all we take a beaker (all dimension are known), then we inject molecules of substance but a uniform flow and with the use of atomizer these atoms or molecules settle down on the bottom of beaker layer by layer when we get full bottom covered with molecules then we find thickness of the layer and estimate no. of atoms in layer with the help of different methods and the we divide it with estimated no. of atoms this way we find the diameter of atoms or molecule then we just divide it by 2. more precisely scientist take extreme precautions while performing the above experiments.

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We need to know the diameter of the wire to calculate the volume and the mass. Number of atoms is: 2,58.1023.r2, where r is the radius of the wire.

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Depending on the thickness of the foil.


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