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Why does temperature of gas drops in an adiabatic process?
because in adiabatic process heat absorbed is zero. and the work is done by internal energy. so internal energy decreases.we know that temperature is directly related with internal energy
Which thermodynamic process takes place when work is done on the system but no energy is transferred to or from the system as heat?
If work is done on a system as compression work and no heat interaction is allowedbetween the system and the surroundings, then you have an adiabatic compression.
In Adiabatic process how the ideal gases increases it's internal energy?
The first law of thermodynamics states that: DU = DQ + DW where DU is the increase in the internal energy of the gas DQ is the heat supplied to the system and DW is the work done ON the system For an adiabatic process, DQ = 0 Therefore, DU = DW It can be thus easily seen that for the internal to increase (DU +ve), DW must be positive, that is work has to be done on the system (in this case the ideal gas). Hence, the gas should be compressed.
Is the work-done in isothermal system is zero why?
If a reaction is carried out in constant temperature and constant volume no work is done and heat exchanged with surroundings is equal to the internal energy.
Which Law of Thermodynamics is relevant when you inflate a tire?
It's the first law of thermodynamics that is applicable when a trre is inflated.If both tyre and pump is considered a part of system than no change in work done. But if a trye with control volume is considered and tyre is inlated , then it's an isolated system with adabatic compressionj taking place. AS we know Q= U +PV. AS process is adiabatic Q is 0 . Increse in pressure or volume or both is accompanied by increase in internal energy of system. At the same time PV(Change ) is the work done by the person inflating the gas.
Why adiabatic curve is steeper than an isothermal curve?
Reason being vaguely adiabatic process is more rapid - process is done so fast that no energy is allowed to enter or exit the system. So P-v variations will be high
Is in adiabatic process the work done is independent of path?
YES.. By first law of thermodynamics, dQ=dW+dU For adiabatic process dQ=0 dW=-dU Above relation shows that the work done is equal to change in internal energy in magnitude which is the property of the system or point function. Thus work done in adiabatic process is a point function.
How does the volume change in an isentropic process?
The entropy of an ideal gas during an isothermal process may change because normally the entropy is a net zero. The change of on isothermal process can produce positive energy.
What are the deference of isothermal and non-isothermal crystallization kinetics study of the fats?
Isothermal crystallization done with respect to time and non isothermal with respect to temperature
Why does temperature of gas drops in an adiabatic process?
because in adiabatic process heat absorbed is zero. and the work is done by internal energy. so internal energy decreases.we know that temperature is directly related with internal energy
Work done is not a state function?
In mechanics,work done(work=force.displacement of body) by a body is independent of path.It only depends on the initial and final state of the body.However in thermodynamics,the work done by an ideal gas(work=pressure.change in volume of gas) depends on the path taken(isochoric,isothermal,isobaric,adiabatic)
Derivation for workdone in isothermal process?
In thermodynamics, an adiabatic process or an isocaloric process is a process in which no heat is transferred to or from working fluid. The term "adiabatic" literally means an absence of heat transfer; for example, an adiabatic boundary is a boundary that is impermeable to heat transfer and the system is said to be adiabatically (or thermally) insulated. An insulated wall approximates an adiabatic boundary. Another example is the adiabatic flame temperature, which is the temperature that would be achieved by a flame in the absence of heat loss to the surroundings. An adiabatic process which is also reversible is called an isotropic process.Ideal gas:For a simple substance, during an adiabatic process in which the volume increases, the internal energy of the working substance must necessarily decrease. The mathematical equation for an ideal fluid undergoing an adiabatic process is,p.v^( γ )where P is pressure, V is volume, andγ =CP/CV=α +1 / α .CP being the molar specific heat for constant pressure and CV being the molar specific heat for constant volume. α comes from the number of degrees of freedom divided by 2 (3/2 for monotonic gas, 5/2 for diatomic gas). For a monotonic ideal gas, γ = 5 / 3, and for a diatomic gas (such as nitrogen and oxygen, the main components of air) γ = 7 / 5. Note that the above formula is only applicable to classical ideal gases and not Bose-Einstein or Fermi gases.For the derivation of work done in an adiabatic process, please visit the link I added below.
Why do adiabatic temperature changes occur?
In adiabatic process heat is neither added nor removed from the system. So the work done by the system (expansion) in adiabatic process will result in decrease of internal energy of that system (From I st law). As internal energy is directly proportional to the change in temperature there will be temperature drop in an adiabatic process.
Example of isothermal process?
An isothermal process is a change in a system where the temperature stays constant (delta T =0). A practical example of this is some heat engines which work on the basis of the carnot cycle. The carnot cycle works on the basis of isothermal.
Which thermodynamic process takes place when work is done on the system but no energy is transferred to or from the system as heat?
If work is done on a system as compression work and no heat interaction is allowedbetween the system and the surroundings, then you have an adiabatic compression.
What is adiabatic heating?
Heating that results from work done on the system, such as when a gas is compressed within a piston.
In Adiabatic process how the ideal gases increases it's internal energy?
The first law of thermodynamics states that: DU = DQ + DW where DU is the increase in the internal energy of the gas DQ is the heat supplied to the system and DW is the work done ON the system For an adiabatic process, DQ = 0 Therefore, DU = DW It can be thus easily seen that for the internal to increase (DU +ve), DW must be positive, that is work has to be done on the system (in this case the ideal gas). Hence, the gas should be compressed.
