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Acceleration = (change in speed) divided by (time interval).
A = 5/4 = 1.25 m/s2
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What is the Acceleration of a car that got up to 45 ms from a rest position in 3 seconds?
Velocity at time 0 sec = 0m per sec Velocity at time 3 sec = 45m per sec Acceleration is 45/3 = 15m per sec if the acceleration is uniform
State whether there can be an object with a constant acceleration but with zero velocity?
yes, if it has a constant acceleration of 0m/s2
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
What is the acceleration of a cheetah that zips past you at a constant velocity of 60mi hr?
0m/s2 because the velocity is constant.
What is 0 meters per second squared?
0m/s2=0
If a car can go from 0 - 100 in 4 seconds what is its acceleration?
(vf-vi)/t or (100m/s - 0m/s) divide by 4seconds. Remember pemdas: parenthesis first, then divide. 100m/s2 divided by four seconds=25m/s
Can changing of velocity results in acceleration. Explain.?
Acceleration is change in velocity over time. a = vf - vi/Δt, where a is acceleration, vf is final velocity, vi is initial velocity, and Δt is the time interval. For example, a car accelerates from rest to 15m/s in 5.9s. What its acceleration? vi = 0m/s, vf = 27m/s, Δt = 5.9s, a = ? a = 27m/s - 0m/s/5.9s = 4.6m/s/s = 4.6m/s2
When throw an object upward and return after 6 seconds what was its initial velocity?
Use the equation vf = vi + gt, where vf is final velocity, vi is initial velocity, g is acceleration due to gravity, and t is time.Known:vf = 0m/sg = -9.8m/s2t = 6sUnknown:viEquation:vf = vi + gtSolution:vi = vf - gtvi = 0m/s - (-9.8m/s2)(6s) = 58.8m/s = 60m/s (rounded to 1 significant figure)
What is the acceleration of a skateboarder traveling 12m per sec?
Acceleration is independent of speed. If the instantaneous velocity of an object is 12m/s and no other information is known, it is impossible to tell the acceleration. However, if the velocity does not change at all over a certain time interval, the acceleration over that time interval is 0m/s2. If other information is given, such as initial/final velocity, time, or displacement, then one of the the "famous five" equations may be used to determine the acceleration.
How to calculate the acceleration of falling body?
TO CALCULATE ACCELERATION OF BODY that is 'g' / 'a' use formula:a=v-u/t where u=0m/s.s=ut+1/2at2.v2-u2=2as or v2-u2=2gh.
What is the magnitude of the acceleration of the car who is traveling along east with a constant velocity?
acceleration is the change in velocity by change in time (often meters/second/second). so, if a car was travelling 10m/s and ten seconds later, it is travelling 20m/s in the same direction, the acceleration would be (20m/s-10m/s)/10s=1m/s/s. with a constant velocity the change in velocity is zero (x m/s - x m/s)/y s=0m/s/s and acceleration is also zero.
What does v equals 0m slash s stand for?
Velocity = 0 metres per second, ie immobility.
