In this case you have a Salt that comes from a binarius acid (HCl) you have to remember in salts you are always using the oxidation number with H (Cl= -1) so Cr is using 3 :) as you have seen im not a English native speaker... sorry for mistakes :D
-1 for each Cl
+3 for Cr
+3 for Cr3+
1
Chromium (III) chloride
S sulfur
Under still milder conditions, chromium metal reacts with the halogens fluorine, F2, chlorine, Cl2, bromine, Br2, and iodine, I2, to form the corresponding trihalideschromium(III) fluoride, CrF3, chromium(III) chloride, CrCl3, chromium(III) bromide, CrBr3, or chromium(III) iodide, CrI3.
(NH3)5Cl3CrIt would be more descriptive to write it like this though [(NH3)5ClCr]2+ 2Cl-
Commercially anhydrous chromium(III) chloride may be prepared bychlorination of chromium metal directly, or indirectly by chlorination ofchromium(III) oxide in the presence of carbon at 650--800 °C, with carbon monoxide as a side-product:[3] Cr2O3 + 3 C + 3 Cl2 → 2 CrCl3 + 3 CO It may also be prepared by treating the hexahydrate with thionyl chloride:[4] CrCl3·6H2O + 6 SOCl2 → CrCl3 + 6 SO2 + 12 HCl
CrCl3: A chloride ion has only a single negative charge; therefore, three of them are required to have the same magnitude of electric charge as a chromium (III) ion.
Because the chromium ion is in its trivalent form.
Chromium (III) chloride
Chromium (II) chloride = CrCl2Chromium (III) chloride = CrCl3 Chromium (IV) chloride = CrCl4
S sulfur
Chromium has four oxidation states: 2, 3, 4, and 6. Chlorine has one, and it's -1. There will be a chloride for each oxidation state of chromium. Here they are: CrCl2 Chromium (II) chloride CrCl3 Chromium (III) chloride CrCl4 Chromium (IV) chloride CrCl6 Chromium (VI) chloride
Under still milder conditions, chromium metal reacts with the halogens fluorine, F2, chlorine, Cl2, bromine, Br2, and iodine, I2, to form the corresponding trihalideschromium(III) fluoride, CrF3, chromium(III) chloride, CrCl3, chromium(III) bromide, CrBr3, or chromium(III) iodide, CrI3.
There is no compound with the formula CrCI3 (uppercase i). You most likelt mean CrCl3, with a lowercase L. This is chromium III chloride.
(NH3)5Cl3CrIt would be more descriptive to write it like this though [(NH3)5ClCr]2+ 2Cl-
Commercially anhydrous chromium(III) chloride may be prepared bychlorination of chromium metal directly, or indirectly by chlorination ofchromium(III) oxide in the presence of carbon at 650--800 °C, with carbon monoxide as a side-product:[3] Cr2O3 + 3 C + 3 Cl2 → 2 CrCl3 + 3 CO It may also be prepared by treating the hexahydrate with thionyl chloride:[4] CrCl3·6H2O + 6 SOCl2 → CrCl3 + 6 SO2 + 12 HCl
The formula of chromium chloride is CrCl3 and the formula for silver chloride is AgCl. The relevant formula unit masses are 158.36 for chromium (III) chloride and 143.32 for silver chloride. The gram atomic masses of chlorine, chromium, and silver are 35.453, 51.996, and 107.866 respectively. Therefore, the mass fraction of chloride in chromium (III) chloride is [3(35.453)/158.36] or 0.671628 and the mass fraction of chloride in silver chloride is 35.453/143.32 or 0.24737. Therefore, to form 75.0 g of silver chloride, (0.24737)(75.0) or 18.55 g of chloride is needed, and this amount of chloride is contained in 18.55/0.6716 or 27.6 g of chromium (III) chloride, to the justified number of significant digits.
The formula of chromium chloride is CrCl3 and the formula for silver chloride is AgCl. The relevant formula unit masses are 158.36 for chromium (III) chloride and 143.32 for silver chloride. The gram atomic masses of chlorine, chromium, and silver are 35.453, 51.996, and 107.866 respectively. Therefore, the mass fraction of chloride in chromium (III) chloride is [3(35.453)/158.36] or 0.671628 and the mass fraction of chloride in silver chloride is 35.453/143.32 or 0.24737. Therefore, to form 75.0 g of silver chloride, (0.24737)(75.0) or 18.55 g of chloride is needed, and this amount of chloride is contained in 18.55/0.6716 or 27.6 g of chromium (III) chloride, to the justified number of significant digits.