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Oxidation Numbers

An oxidation number is a positive or negative number that indicates how many electrons an atom has gained, lost, or shared to become stable.

500 Questions

What is the oxidation number of O2?

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The oxidation number for 'O2' is zero(0).

However, when calculating oxidation numbers in compounds containing oxygen, then the oxygen is used as a standard at '-2'.

So as an example using potassium permanganate (KMnO4), what is the oxidation number of manganese (Mn).

In solution this dissolves producing the permanganate ion (MnO4^(-).

Note the charge on the ion is '-1'.

Since there are 4 oxygens present , then the oxidation of the oxygen moiety is 4 X -2 = -8 .

So creating a little sum

Mn + -8(oxygen moiety) = -1 (overall charge on the ion).

Mn + -8 = -1

Add '8' to both sides

Mn = (+)7 is the oxidation number of manganese.

So the formula could be written as KMn(VII)O4 . (Note the Roman numerals for oxidation number).

Why is the oxidation number of Br in BrO3 5?

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BrO3 is an anion of minus one (-1) charge.

BrO3^-1

Using oxygen as the standard at '-2'

Then the oxygen moiety is 3 X -2 = -6

So doing a 'little' sum

-6 + Br = -1

Add '6' to both sides

Br = 5 (The oxidation number of Br).

NB Using '-2' for oxygen is a good standard for most molecules/ions. However, oxygen's oxidation number does vary , but not in very many molecules/ions.

What is the oxidation number of C2H4O?

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C2H4O oxidation number is -1

2x+1(4)+1(-2)=0

2x+4-2=0

2x+2=0

2x=-2

x=-2/2

x=-1

What is the oxidation number of Cr in K2Cr2O4?

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K2Cr2O4

Using oxygen at '-2' as the standard.

Then the oxygen moiety is 4 x -2 = -8

Since K is only +1, and there are 2 x K , then this moiety is '+2'

The overall charge on the molecule is zero.

So we make a sum

  • 2 + 2Cr - 8 = 0

2Cr = 8 - 2 = 6

Cr = +3 ( THe oxidation No. of Cr'.

The oxidation number of sulfur in h2so4 is?

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To calculate oxidation numbers. Use oxygen at '-2' as the standard. It does vary in specific cases , but '-2' is the best starting point.

In H2SO4

There are 4 x oxygen , hence 4 x -2 = -8

So the oxygen moiety is '-8'. So the hydrogen and Sulphur MUST come to '+8'.

Since hydrogen is 'H^+' in Sulphuric Acid, its oxidation no. is '+1'

So there are 2 x hydrogen , hence 2 x +1 = +2

Since sulphuric acid is a neutrally charged compound, then

+2 + S - 8 = 0

Hence S = 8 - 2 = +6 THe oxidation no. of sulphur. in sulphuric acid.

NB The oxidation no. of sulphur can vary is different compounds.

What is oxidation number of NHO3?

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NHO3 ???? I think you mean HNO3 ( Nitric Acid).

NB With all mineral acids the 'H' is the first letter.

To find the oxxidation number., use oxygen at '-2'

Since there are 3 oxygens, then the oxidation state of the oxygen component is 3 x -2 = -6 .

Since also hydrogen is always '+1' then we can constract a sum

1 + N -6 = 0 (NB We equate to zero because it is a neutrally charged molecule.

N - 5 = 0

N = 5 the oxidation state of nitrgoen .

How do you find a oxidation number?

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Use oxygen at '-2' as the standard.

However, oxygen can vary, but initially use '-2'

So why is potassium permangate (VII) have the 'VII/7' in the name . It is the oxidation number of the manganese.

How do we gert there.

The formula is KMnO4

So there are four oxygens each at '-2' then overall the oxygen component is 4 x -2 = -8

Since the K is a Group '1' metal its oxidation is K^+ = +1

So creating a little sum,

+1 + Mn - 8 = 0 (Zero because it is a neutral molecule)

Hence

Mn - 7 = 0

Hence Mn = 7 ( 'VII' latin numerals are used for oxidation numbers).

NB Oxidation number refers to the numbers of electrons, of a given atom, involved in the bonding process.

NNB Sulphur has several oxidation numbers. They are: -

-2 in H2S

0 in elemental sulphur

+2 in SCl2

+4 in SO2

+6 in SO3 / H2SO4

What the oxidation numbers of K2SiO3?

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K2SiO3 ( potassium silicate)

Use oxygen at '-2' as the starting point.

Since there are 3 x oxygen , then the oxygen component is 3 x -2 = -6

So the K & Si must sum to '+6'

Since K oxidises to '+1' as in 'K^+', then the 'K' component is 2 x 1 = 2

Hence we have 2 + Si + - 6 = 0 (neutral molecule)

Then by a simple sum Si is +4.

So the oxudation states of each element are

K = +1

Si = + 4

O = -2

What is the oxidation number of S in S2O8?

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This is the thiosulfate ion. Sulfur shows +6 oxidation number.

What is the oxidation number of S2 in S2O3?

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The oxidation No. is '3'.

To calculate oxidation numbers, remember the 'yardstick' of oxygen at '-2' . There are a few exceptions to this, but work from '-2'.

S2O3

There being 3 x oxygen present, the the oxygen moiety is '3 x -2 = -6

So the sulphur moiety must be '+6', in order to maintain charge neutrality.

Hence 2 x S = 2 X x = 6

x = 3

So sulphur oxidation is '+3'.

What is the oxidation number charge of the ion?

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The oxidation number is a measure of the charge an atom would have if all its bonds were 100% ionic. It can be positive, negative or zero.

What is oxidation number of carbon in Hydronium?

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In the hydronium ion (H3O+), the oxidation number of carbon is +3.

What is the oxidation number of each element in NaCl?

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The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.

Can sodium chloride undergo combustion?

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No, actually sodium chloride can be considered the "ash" of burning metallic sodium in a chlorine gas atmosphere. The ash of combustion will not undergo further combustion.

What is oxidation number of Cu?

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If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero.

If the question is Cu2+, then the oxidation number is +2.

What is the oxidation number of Cu in CuSO4?

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-2 for sulphur and +1 for each copper.

What is Oxidation numbers for SO4?

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This should be SO4-2 ion. sulfur shows +6 in this ion.