Wjat is 'li3po3'. ??? If you mean Li3PO3, then note the use of Capital and small case letters.
For lithium phosphite (Li3PO3) , use oxygen as the standard at '-2'
Since there are three oxygens, then the overall oxidation is '-6'
The phosphite anion 'PO3^(3-) has an overall charge of '-3', there being three positives from the lithium (3 x Li^(+)).
So doing a 'little sum'
P + (3 x -2) = -3 ( The anionic charge).
P + -6 = -3
Add ''6' to both sides.
Hence
P = + 3 (The oxidation state of phosphorus.
NB Phosphorus is in the same Group(V) as nitrgoen, and like nitrogen , it can exhibit variable oxidation states.
Compare with Li3PO4 ( lithium phosphate) . In this compound phosphorus in is oxidation state ' +5 '.
Also Note the suffix in the name '+3' is '---ite' , and '+5' is '---ate'.
The oxidation number of calcium (Ca) is +2 and the oxidation number of phosphorus (P) is -3. Therefore, in Ca₃P₂, the oxidation number of calcium is +2 and the oxidation number of phosphorus is -3.
Phosphorous, or P, has a zero oxidation number in the element. Common oxidation numbers are:- It has a -3 in phosphides, where it forms the P3- ion It has a +3 in oxidation number in for example P4O6, and PCl3 It has a +5 oxidation number in for example P4O10 and PCl5
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
The oxidation number of P in P2O5 is +5. This is because oxygen typically has an oxidation number of -2, and there are 5 oxygen atoms in P2O5. The sum of the oxidation numbers in a neutral compound must equal zero, so the oxidation number of P is calculated as +5.
The oxidation number of P in H2PO2- is +1. This is because each hydrogen atom has an oxidation state of +1, and the overall charge of the ion is -1. Therefore, the oxidation number of phosphorus must be +1 to balance out the charge.
The oxidation number of calcium (Ca) is +2 and the oxidation number of phosphorus (P) is -3. Therefore, in Ca₃P₂, the oxidation number of calcium is +2 and the oxidation number of phosphorus is -3.
Phosphorous, or P, has a zero oxidation number in the element. Common oxidation numbers are:- It has a -3 in phosphides, where it forms the P3- ion It has a +3 in oxidation number in for example P4O6, and PCl3 It has a +5 oxidation number in for example P4O10 and PCl5
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
The oxidation number of P in P2O5 is +5. This is because oxygen typically has an oxidation number of -2, and there are 5 oxygen atoms in P2O5. The sum of the oxidation numbers in a neutral compound must equal zero, so the oxidation number of P is calculated as +5.
The oxidation number of P in H2PO2- is +1. This is because each hydrogen atom has an oxidation state of +1, and the overall charge of the ion is -1. Therefore, the oxidation number of phosphorus must be +1 to balance out the charge.
The oxidation number of P in PCl3 is +3. This is because chlorine typically has an oxidation number of -1, and there are three chlorine atoms in PCl3, giving a total charge of -3. To balance this charge, the oxidation number of P must be +3.
The oxidation number of P in NaH2PO2 is +1. This is because Na and H have standard oxidation states of +1 and +1 respectively, and the overall molecule has to be neutral, so the oxidation number of P must be +1 to balance the charges.
The oxidation number of PH4 cannot be determined because phosphorus (P) does not have a fixed oxidation number in this compound.
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
The oxidation number of phosphorus (P) in PF3 is +3. This is because fluorine (F) has an oxidation number of -1, and the overall molecule PF3 has a total charge of 0.
The oxidation number of phosphorus (P) in H3PO5 is +5. Each hydrogen atom has an oxidation number of +1, and the oxygen atoms have oxidation numbers of -2. The sum of the oxidation numbers in a neutral compound must equal zero.
P= -4