In the electroplating process, iron (Fe) is typically oxidized. This occurs because iron serves as the anode, where it loses electrons and forms iron ions. Silver (Ag), being reduced at the cathode, gains these electrons and is deposited onto the surface to be electroplated. Thus, in this scenario, iron is the material that undergoes oxidation.
Ag(s)
The iron is oxidized and the silver is reduced.
Iron (Fe) is a metal that can be oxidized by two common ions: copper ions (Cu^2+) and silver ions (Ag^+).
The answer is not c.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
Ag(s)
Ag(s)
During electroplating silver onto iron, iron gets oxidized to iron ions (Fe^2+ or Fe^3+). This oxidation process is essential for transferring iron atoms from the iron surface to the silver coating during electroplating.
AgAg(s)-
AgNO3
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
In the electroplating process, during the oxidation reaction, silver atoms are oxidized to Ag+ ions for silver plating, and iron atoms are oxidized to Fe2+ ions for iron plating. This allows the metal ions to be deposited onto the object being plated.
In this reaction, Ag^+ is the oxidizing agent. It undergoes reduction by accepting electrons from Fe to form silver metal, while Fe gets oxidized to Fe^3+ in the process.
Ag+ (apex)
Fe(s) + 3AgNO3 ---> Fe(NO3)3 + Ag(s) The oxidation # of Ag on the left is 1+ and on the right it is zero. It has gained electrons and has been reduced.
The iron is oxidized and the silver is reduced.
Iron (Fe) is a metal that can be oxidized by two common ions: copper ions (Cu^2+) and silver ions (Ag^+).