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Q: Find the distance between the points-2 -10 and -8 -2?
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Find the distance between these points A32 B910?

If the points are (3, 2) and (9, 10) then the distance works out as 10


Find the distance between the points -2 -10 and 10 6?

The sq.root of 122+162=20


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Find the distance between points -6 1 and 10 -8?

If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36


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(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.


Find the distance between the points -2 -10 and -8 -2?

The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.


Find the distance between 5 2 and 2 4 If necessary round your answer to the nearest hundredth?

Distance is sq rt ((x2-x1)2+((y2-y1) So 9+1 is 10. sqrt of 10 is 3.16 distance rounded to hundredths


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A scale where the distance between 1 and 2 is the same as the distance between 2 and 3; and so on. By way of contrast, in a logarithmic scale, the distance between 1 and 10 would be the same as the distance between 10 and 100, or 100 and 1000. There are many other scales.


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What is the distance between the points (10 12) and (4 36)?

The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.


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