10
If the points are (3, 2) and (9, 10) then the distance works out as 10
The sq.root of 122+162=20
10
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
Distance is sq rt ((x2-x1)2+((y2-y1) So 9+1 is 10. sqrt of 10 is 3.16 distance rounded to hundredths
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
The nearest multiple of 10 to 634 is 630. To find the nearest multiple of 10, you need to determine the distance between the number and the nearest multiples of 10. In this case, the distance between 634 and 630 is 4, which is smaller than the distance to 640. Therefore, 630 is the nearest multiple of 10 to 634.
10 units.
The distance between these two places is 10 miles. This distance is only approximate. This is not exact distance.
A scale where the distance between 1 and 2 is the same as the distance between 2 and 3; and so on. By way of contrast, in a logarithmic scale, the distance between 1 and 10 would be the same as the distance between 10 and 100, or 100 and 1000. There are many other scales.