(x-9)(x-5)=0
x²-14x+45=0
x2 + 3x - 5 is an expression, not an equation. An equation may have roots, an expression does not. However, x2 + 3x - 5 = 0 is an equation and its roots are -4.1926 and 1.1926 (approx).
8
x2 - 2x - 15 = 0
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
If you mean y = 2x+5 then the perpendicular slope is -1/2
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
x2 + 3x - 5 is an expression, not an equation. An equation may have roots, an expression does not. However, x2 + 3x - 5 = 0 is an equation and its roots are -4.1926 and 1.1926 (approx).
You don't have an equation there.
19
find the sum and product of the roots of 8×2+4×+5=0
x2 + 2x + 5 = 0 is already in the form ax2 + bx + c = 0 so to find the discriminant, D, you use D = b2 - 4ac Then if D is greater than 0 the equation has 2 real roots; if D = 0 the equation has one real root and if D is less than 0 the equation has no real roots. So to check this we work out D but we need to know what a, b and c are. From the equation we can see that a = 1 b = 2 c = 5 so putting these values in to find D: D = (2)2 - 4(1)(5) = 4 - 20 = -16 so the equation x2 + 2x + 5 = 0 has no real roots.
-3
8
(x - 3) and (x - (-5)).
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
The roots are: x = -5 and x = -9