-10x + 2y = 14 Initial problem
(-10x + 2y) + 10x = (14) + 10x add 10x to each side of the equation
2y = 10x + 14 value after the addition
(2y)/2 = (10x +14)/2 divide by 2
y = 5x + 7 resultant eqution
y = mx + b is the standard form
m = 5 and b = 7 via substitution
slope of standard formula = m, therefore slope = 5
by definition b is the Y-intercept, therefore Y-intercept is 7
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Note the Y-intercept is where the line crosses the Y Cartesian coordinate axis
at x = 0. therefore it can be calculated as
Given y = 5x + 7, and x = 0
then
y = 5(0) + 7
y = 0 + 7
y = 7
or in logical terms dialectical analysis
Thesis is y = 5x + 7
Antithesis is x = 0
Synthesis is y = 7
The slope of the perpendicular is -(1/2) .
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
find the constant of variation and the slope of the given line from the graph of y=2.5x
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Slope = 4
the slope is 0
The equation for the slope of a line is y=mx+b
That's a vertical line; the slope is not defined.
7
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
The slope of the perpendicular is -(1/2) .
Slope of a line perpendicular to x-y=16
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
find the constant of variation and the slope of the given line from the graph of y=2.5x
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
45
-14