Top Answer

The graph of [ y = 4x + 2 ] is a straight line with a slope of 4.

Any line with a slope of 4 is parallel to that one, and any line parallel to that one has a slope of 4.

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0find the constant of variation and the slope of the given line from the graph of y=2.5x

You find the slope of the tangent to the curve at the point of interest.

Find the slope of a graph of velocity vs. time.

Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.

The slope of the graph does not exist. And in the context of "this" problem it means absolutely nothing.

The slope of y=mx+b is always the "m". Therefore in y=1.5x-4.5 the slope is 1.5/1. Below you will find a graph for this linear equation.

Find the slope of the tangent to the graph at the point of interest.

The slope on a position-time graph is the velocity.

The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.

2y = 5x + 8Divide each side by 2:y = 2.5x + 4The slope of the graph is 2.5 .The y-intercept is 4.

first you put the cone on a graph and if you know how to find slpoe rise/runlay it flatif you do not know how to get slope check out my other answer on how to get slope

This algebra lesson explains how to find the slope of a line by looking at its graph. To get from the point (-2, -1) to the point (4, 3), you rise up 4... and run 6.

you can write it in the form y=mx+b where y and x are constants, m is slope, and b is the y-intercept you can find the slope (m) by taking y1-y2/x2-x1 with any 2 points on the graph ( it doesn't matter which point comes first) if you have a graph, to find b (y-int) locate the point where x equals zero, if there is none, than the y-int is zero if you don't have a graph plug in m along with any point on the graph to find b

find the tangential slope at the time intervals and you will get velocity.. then just plot it on the graph

You can find the slope of this equation without even drawing or even trying to visualize a graph in your mind, simply by referring to the following formula: y= mx+b, where m is the slope and b is the y-intercept Now, the equation you are given fits this formula rather nicely, y=5x-10, so one deduces that the slope is 5 and the y-intercept is -10.

we can find the young's modulus from graph by slope method. By constructing the triangle between elastic region to yield region.

That's a vertical line; the slope is not defined.

An equation in the form y = mx + c has slope m and intercept c. y - 9 = 0.75x => y = 0.75x + 9 So slope = 0.75 and intercept = 9

This graph is a straight line that cuts the Y-axis at - 6 and has slope 2. You might find the related link to be helpful but you need to read the directions if you want to use it.

You find the point(s) at which the slope of the curve is greatest.

Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?

The slope is the magnitude of the line upwards or downwards, commonly referred to as "rise over run". The rise is how much the graph goes up in a certain distance, and the run is how much the graph goes over horizontally that same distance. To find the slope in that situation, you have to divide the rise by the run.

The slope of the line 4x-3y equals zero is said to be 4/3.

Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.

It is a straight line through the origin with slope of 5. So start at (0,0) and go up 5 and over 1 to find the next point. Join those two points with a line and you can see the graph.

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