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Assuming that is y = 4 - x2 → x2 = 4 - y

Crosses y axis (x = 0) at y = 4

volume = π∫x2 dy

= π 1∫4 4 - y dy

= π[4y - y2/2]14

= π[(16 - 16/2) - (4 - 1/2)]

= 9/2 π

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Q: Find the volume of the solid formed when the region bounded by the parabola y 4-x 2 and the line y 1 is rotated about the y axis?
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