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the answer is C

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more strongly attracted to the fluorine atom than the other atom in the bond.

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13y ago
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6mo ago

more likely to be pulled towards the fluorine atom. This results in a polar covalent bond, with the fluorine atom having a partial negative charge and the other element having a partial positive charge.

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Q: Fluorine is the most electronegative element therefore when it forms bonds with another element the electrons are?
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What is an electronegative?

An electronegative atom is an atom that can attract a bonding pair of electrons from another atom. Fluorine is the most electronegative element.


What is an electronegative atom?

An electronegative atom is an atom that can attract a bonding pair of electrons from another atom. Fluorine is the most electronegative element.


When fluorine bonds with another element the electrons do what?

Fluorine has a stronger attraction to electrons than any other element, so when it bonds to another element that element is going to either donate electrons to the fluorine, or share electrons with fluorine getting the disproportionate share.


Why is fluorine most electronegative than oxygen?

Electronegativity is an atoms relative ability to remove an electron pair in the formation of a covalent bond. I.e. an atoms ability to steal a pair of electrons from the outer ring of another atom to make a covalent bond, (like a contract to share electons in order to fill there outer shells and become stable) Across the periodic table (left to right) this gets harder to do due to an increase in attraction forces between the nuclear charge and the outer electons. Therefore across the periodic table 'more' electronegativity energy is required to remove those electrons. Down the periodic table, from top to bottom attraction forces between the electrons in the outer shell and the central nuclear charge decreases (shielding effect of sub levels and increased atomic radius), this make it easier for the electrons to be stolen, so there is less electronegativity required. Fluorine is the highest and furthest to the right, making it the most electronegative. (Helium and Neon etc have full outer shells so arent involved in covalent bonds)


When two fluorine atoms share a pair of electrons the bond that forms a?

A fluorine atom forms a covalent bond with another fluorine atom to produce the fluorine molecule which is gaseous at room temperature.


How do valence numbers help determine the oxidation number?

oxidation number is defined as a positive or negative number corresponding to the charge that an atom in a molecule or ion would have if the electron pairs belonged entirely to the more electronegative atom. in this case, they're talking about 'valance electrons'. An example would be...fluorine has 7 valance electrons. when bonded with another element, it would in almost all of the cases want to gain 1 more electron to have a full valance shell of 8 electrons. Therefore, it would become F -1 As a result, fluorine's oxidation number becomes -1, the same as its CHARGE when bonded to ANOTHER element (NOT ITSELF) when fluorine bonds to itself to become Fluorine gas, its oxidation number is zero. that goes for all ....elements which bond with itself to form a diatomic molecule (oxygen gas, hydrogen gas, etc) --gh ---


Why is FCl polar but F2 is not?

A molecule is polar is a result of differences in electronegativity; that is, one atom has a stronger pull on electrons than another. Flourine (F) is more electronegative than chlorine (Cl), and so tends to pull electrons to its side of the molecule. This makes FCl polar. F2 consists of two atoms of fluorine, which are identical and thus have the same electronegativity. Therefore, the molecule is nonpolar.


Why is fluorine more electronegative than chlorine?

A qualitative answer is that fluorine is more electronegative than chlorine because the outer electrons in fluorine are less "screened" from their attraction to the positive nucleus, because there are more non-valence electrons in chlorine.Two factors affect the electronegativity of an element:Nuclear charge: If the element has a large nuclear charge it will attract electrons to it more readily than one with a small nuclear charge.The radius of the atom: If the element is small then the effect of the pull from the nucleus will be greater (due to physical distance between the nucleus and the outside of the atom and the effect of electron shielding - shells of electrons reducing the 'pulling' power of the nucleus). As we go across a period the atomic radii of the atoms decreases. As we go down a group the atomic radii of the atom increases (even though the nuclear charge also increases, the atomic radii increases to a greater extent which practically cancels out the effect of the increased nuclear charge)Therefore the most electronegative element is Fluorine, followed by Oxygen, Nitrogen and Chlorine: F>O>N>C


What is the name of electrons in the outermost shell that an atom can gain lose or share with another atom?

A Fluorine atom has an atomic number of 9. Draw out the electron shell diagram for Fluorine. Is a Fluorine atom more likely to gain, lose or share electrons to fill its valence shell?


Why flourine is most reactive?

The thing that makes fluorine so reactive is its electronegativity.


Why are atoms of bromine so reactive?

Bromine is quite reactive because it is highly electronegative. Electronegativity is a chemical property that measures the ability for an atom to gain electrons from another atom. Thus, the more electronegative an atom is, the more reactive it is. Generally speaking, as you move up a group and across a period on the periodic table, the electronegativity increases. Fluorine has the greatest electronegativity, while francium has the lowest.


What determines the electron distribution between two atoms in a bond?

The electronegativity of each atom; that is, the ability of the atom to withdraw electrons. Electronegativity tends to increase as you go up and to the right of the periodic table, with fluorine having the highest electronegativity. The more electronegative the atom, the more it will "hog" the electrons. So, for instance, in the molecule H-F (hydrogen fluoride) most of the electrons are spending their time around fluorine because it is highly electronegative. This causes two poles to form, with fluorine having a slightly negative charge and hydrogen having a slightly positive charge. This molecule is then said to be highly "polar".