The equation you are looking for is, amperage when kilowatts are shown. This is for three phase systems. To change watts to kilowatts divide watts by 1000. Amps = kW x 1000/1.73 x Volts x pf.
Use .8 for pf on large motors.
It should me stamped on the information plate. If this is not on it, then there will be the running current stamped on the plate. Multiply this by the supply voltage to find the power in watts. Take the horsepower of the motor and multiply it by 746. There are 746 watts in 1 HP. It is also the same for single phase motors.
I think what you mean to ask is; "The difference between a current sensing, and potential sensing relay. I've never heard of a potential relay. Relays are "pulled in" by applying voltage to the coil, typically 120Vac, or 24Vdc. A current sensing relay will close its contacts when it is wired to sense a particular amount of current. Instead of applying voltage (turning on) the relay, it closes contacts when current flows through it. HVAC technician ***** A 'current' relay has a coil of low resistance wire (heavy gauge wire, few turns), and is energised only by a large current, such as the initial current of a motor starting. The relay coil is wired in series with the run/main winding of the motor, and the relay contacts are normally open. As the motor tries to start, the large current closes the relay, which momentarily brings the start/aux winding into circuit, allowing the motor to go. Used for split-phase and capacitor-start motors. A 'potential' relay has a coil of high resistance wire (light wire, many turns), and is wired in parallel with the start/aux winding, and the relay contacts are normally closed. At initial motor start-up, high curent will flow through both the run and start windings of the motor. As the motor reaches operating speed, the current reduces, and a "back EMF" is produced allowing current to now pass through the potential relay coil, and open the contacts. Used for capacitor-start and cap-start cap-run motors. Another HVAC technician. you sound like a real ahole. everyone in the field calls them potential relays, in addition look at a schematic on an AC and you'll find "PR" potential relay. what a dip#hit
You can find this part at your local automotive store by taking it in. You can also look online to find out where this part is sold.
We Can find the Electric Motor in the vehicle as a self, which helps to start the engine initially.
E.a.c
It depends on the compressor's total wattage. Watts = Amps x Volts. Find these values from the nameplate on the compressor. As the device is a motor extra current has to be available for the motor starting current. When you find your answer in watts allow another 150% for starting current.
Depends on what sort of motor it was. If it was the sort you find in an ordinary electric drill, then it would slow down. But rememer, the only way you can reasonably reduce the current in to motor is to reduce the voltage in the supply. A motor takes what current it can, dependent on Ohm's Law. To reduce the current, reduce the voltage. But in a three-phase motor, the speed being dependent on the rotation of the phases, it would more or less stay the same. But this assumes it's not under load. A load would cause it to slow down.
First find the ratio of the transformer. 6600/220 volts. Second find the secondary current, I = W/E, 99000/220. Third divide the secondary current by the transformer ratio. The answer will be the primary current. To check your answer (W (or VA) = V x A) multiply the primary current times the primary voltage and the secondary current times the secondary voltage and they should both equal the transformer's kVA.
No can do until you can provide the current rating in Amperes.
The first thing you have to do is find the full load amps of the motor. The wire size feeding the motor has to be 125% of the full load current. The breaker is usually 250% of the full load current. If the voltage and amperage had been added to the question the exact breaker size could have been calculated.
TMNT
A motor can be connected up to a car battery to store the power produced when it runs as a generator, but you will find that when current is drawn the motor needs more work to spin it, it will not spin so easily. That is because of conservation of energy.
Find out how much current the motor draws, then look up wire tables to find out the size of wire. Ask an electrician if you are not unfamiliar with this because working at 6.6 kV is definitely lethal for the unqualified.
It should me stamped on the information plate. If this is not on it, then there will be the running current stamped on the plate. Multiply this by the supply voltage to find the power in watts. Take the horsepower of the motor and multiply it by 746. There are 746 watts in 1 HP. It is also the same for single phase motors.
1)may be voltmeter or clipon meter will be connected across the winding. 2)or in motor winding we must find amp current and aramture resistance nd then find the ratings 3)formula is rated kva of motor*1000/base kva for transmission line.
Index or Glossary
To find Current, it's very easy.