The general formula for distance traveled under uniform acceleration is:
S = v0t + at2 / 2
In our case, the initial velocity is in opposite direction that acceleration.
Let's choose a direction of our axis of displacement: let it face downwards. In this coordinate system, v0 will be
v0 = -9.75 m/s (converted from 32 ft/s)
a = g = 9.81 m/s2
Our formula will then take form:
S = -9.75 * 11 + 9.81 * 112 / 2 = 486.26 m
or in feet: S = 1595.32 ft
yes
Terminal velocity.
Take an accelerometer with you when you jump, and at the point that it reads, "zero", the terminal velocity has been reached.
Yes, several manned vehicles have reached escape velocity, which is about 25,000 miles per hour. The Apollo spacecraft used during the moon missions reached escape velocity en route to the moon. Also, the Space Shuttle reached escape velocity when it orbited the Earth or traveled to the International Space Station.
When the velocity stops changing, then, by definition, the acceleration is zero.
The song is Red Balloon by the Dave Clark Five, it reached #7 in 1968.
the terminal velocity is the total speed that its take an object to reach the point it required from the initial velocity
When terminal velocity is reached, the gravitational force is balanced with the force of resistance.
Depends on if the object has reached it terminal velocity. From an energy standpoint, yes, as long as there is no appreciable loss of energy due to friction. From a common sense standpoint, it will also bounce higher.
That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.
Perhaps you mean Terminal Velocity, as in a parachute fall? This is the maximum speed reached in the fall. Final velocity will be zero, assuming you arrive on the ground.
Zero, by definition.