v=ir
12=i20
i = 0.6 Amp
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
a circuit with no resistance or zero resistance can be considered as open circuit in which the current is zero. without resistance the circuit just becomes open ()
In a circuit , current is inversely proportional to the resistance.
No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce
The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.
Low current detected by ECU (such as an open or higher then expected resistance).
Resistance is generally used to control the flow of amount of current in the circuit.
It is halved. coz voltage=current * resistance