v=ir
12=i20
i = 0.6 Amp
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
A digital multimeter (DMM) must have a current measurement scale appropriate for the expected current in the circuit. Choose a scale that is equal to or higher than the maximum expected current in the circuit to ensure accurate measurements and to prevent damage to the DMM.
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
When you increase the resistance in a circuit, the current (amps) in the circuit will decrease. This is because Ohm's Law states that current is inversely proportional to resistance, so as resistance increases, current decreases.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
As long as the voltage between the ends of the circuit remains constant, the current through the circuit is inversely proportional to the total effective resistance of the circuit.
a circuit with no resistance or zero resistance can be considered as open circuit in which the current is zero. without resistance the circuit just becomes open ()
Low current detected by ECU (such as an open or higher then expected resistance).
In a circuit , current is inversely proportional to the resistance.
No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce