Given that there are 512 bytes per sector calculate the hard drive storage for the following heads32 tracks cylinders1024 sectortrack63?

Answer 1

1.05 gigabytes i believe



For those of you in Mr. Hupps class at Aviation academy this is the answer to Chapter 7 number 8

and now a shout out to my teacher

HI MR. HUPP!!!!!!!!!!!!!!!

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(Addition from Kimberly)
It's actually 1.0569GB which rounds up to 1.06GB

The formula is:
32*1024*63*512=1056964608
1056964608/1024=1032192 KB 1032192/1024=1008 MB

Answer 2

If a person is going to calculate the hard drive storage for each of the following heads they will need to know what the heads are. Knowing this will allow them to know what the storage would be for each one.

Answer 3

1,056,964,608 Bytes

1,032,192 KB

1,008 MB forumla is ; cylinders (tracks) x heads x sector/tracks x bytes per sector. divide by 1,024 to break the bytes down into KB divide by 1,024 again to break the KBs down into MBs. Note: An older BIOS has capacity limitations. Standard INT 13 limitation is (CHS [1024 x 256 x 63] x 512 A newer BIOS would support the new INT 13 Extentions and LBA (Large Block Access) mode and FAT32 or NTFS are required to achieve full capacity.

Answer 4

You have not provided enough information for an answer. Namely, the number of sectors on the hard drive.

Answer 5

The formula for calculating hard drive storage is:

(heads)*(tracks)*(sectors)*(bytes per sector) = bytes

Usually there are 512 bytes per sector

32*1024*63*512=1056964608