52.4 cm
The answer will depend on whether the length is the hypotenuse or one of the legs of the triangle.
The way you can work out the length of a triangle is if you are given the height and the area of that triangle ( this works of you don't want to measure it) or you could just measure it.
If you mean angles of 150 degrees, 20 degrees and 20 degrees then it is impossible to construct such a triangle because the angles in any triangle add up to 180 degrees and the angles given add up to 190 degrees.
The sum of the angles inside a triangle is equal to 180°. We are told that angle a is 57°, and that angle b is 73°. This tells us that angle c is is (180 - 57 - 73)°, or 50°. We are also given the length of side ab, 25cm. With that, we can use the sine rule to calculate the length of side ac: sin(b) / |ac| = sin(c) / |ab| ∴ sin(73°) / |ac| = sin(50°) / 24cm ∴ |ac| = 24cm · sin(73°) / sin(50°) ∴ |ac| ≈ 29.96cm
Given side lengths of 8 units, an equilateral triangle will have an altitude of 7 (6.9282) units.
In order to find length BC the length of AC or length of the hypotenuse must be given
If you are really talking about a closed triangle ABC, then the length of side "a" (given as 19) does not matter in the calculation. Sum of the angles of a triangle is 180 degrees. Angle B and C add up to 15 + 65 = 80 degrees. Hence angle A is (180 - 80) = 100 degrees
Assuming a plane triangle and you are referring to interior angles c equals 100 degrees
This is not a triangle. All three angles of any triangle must always add up to 180o. The angles you gave add up to only 59.9o.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
It is 12.2 degrees.
67 degrees
It is: 0.5*length squared*(sin 60 degrees)
A scalene triangle would fit the given conditions
It is an obtuse or scalene triangle having the given angles
The answer depends on whether the base is one of the legs of the right angle or the hypotenuse. Also, a triangle cannot have a diagonal.
No triangle exists with the given angle measures. None because the given angles add up to 190 degrees and the 3 angles in any triangle add up to 180 degrees.