y+4=x-3 (get y by itself)
y=x-7 (x is your slope and -7 is your b value)
slope intercept from (y=mx+b)
so it would be a slope of 1 starting at -7 on the y-axis
sorry cant graph on here or i dont know how to
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
the graph is moved down 6 units
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
The graph of that equation is a circle, centered at the origin, with radius = 2 .
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
the graph is moved down 6 units
y=-10x-4
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 + 8 = 0, then x3 = -8, therefore x = -2 -2 x -2 = 4 4 x -2 = -8
Upwards.
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
(0,4) and (-2, 0)
The graph of that equation is a circle, centered at the origin, with radius = 2 .
That's not an equation, so there's nothing to graph. Simple way to tell: There's no "equals" sign in it.