HBr + NaOH ------> NaBr + H2O
This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Using the balanced chemical equation for the reaction between HBr and NaOH (1:1 ratio), we can determine the moles of NaOH used. From the volume of NaOH used, we can then calculate the moles of HBr present in the sample. Finally, dividing moles of HBr by the initial volume of the sample (in liters) gives the molar concentration of HBr.
A student could use the 0.10 M NaOH solution in a titration experiment to determine the concentration of an aqueous solution of HBr by slowly adding the NaOH to the HBr solution until the equivalence point is reached. By monitoring the volume of NaOH required to neutralize the HBr solution, the student can calculate the concentration of the HBr solution using the equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of NaOH and C2 and V2 are the concentration and volume of the HBr solution.
The products of the reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) are sodium bromide (NaBr) and water (H2O). This is a neutralization reaction where the acid (HBr) reacts with the base (NaOH) to form a salt (NaBr) and water.
The balanced chemical equation for the reaction between NaOH (sodium hydroxide) and HCl (hydrochloric acid) is: NaOH + HCl -> NaCl + H2O In this reaction, sodium hydroxide reacts with hydrochloric acid to form sodium chloride and water.
NaOH (aq) + HBr (aq) --> H2O (l) + NaBr (aq)
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
Using the balanced chemical equation for the reaction between HBr and NaOH (1:1 ratio), we can determine the moles of NaOH used. From the volume of NaOH used, we can then calculate the moles of HBr present in the sample. Finally, dividing moles of HBr by the initial volume of the sample (in liters) gives the molar concentration of HBr.
A student could use the 0.10 M NaOH solution in a titration experiment to determine the concentration of an aqueous solution of HBr by slowly adding the NaOH to the HBr solution until the equivalence point is reached. By monitoring the volume of NaOH required to neutralize the HBr solution, the student can calculate the concentration of the HBr solution using the equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of NaOH and C2 and V2 are the concentration and volume of the HBr solution.
The products of the reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) are sodium bromide (NaBr) and water (H2O). This is a neutralization reaction where the acid (HBr) reacts with the base (NaOH) to form a salt (NaBr) and water.
Al2O3 + 6HBr = 2Albr3 + 3H2O
The reaction of 2Br2 + 2H2O → 4HBr + O2 involves the oxidation of bromine (Br2) by water (H2O) to form hydrogen bromide (HBr) and oxygen (O2). Bromine is reduced to HBr, and oxygen gas is released as a byproduct.
The balanced chemical equation for H2 plus Br2 produces 2 HBr.
None. This is a metathesis reaction, and thus nothing is produced but a combination of the reactants (NH4Br, for example).
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o
The balanced chemical equation for the reaction between NaOH (sodium hydroxide) and HCl (hydrochloric acid) is: NaOH + HCl -> NaCl + H2O In this reaction, sodium hydroxide reacts with hydrochloric acid to form sodium chloride and water.
NaOH (aq) + HBr (aq) --> H2O (l) + NaBr (aq)
The balanced chemical equation for the reaction between hydrobromic acid (HBr) and sodium hydroxide (NaOH) is: HBr + NaOH → NaBr + H2O This equation shows that one molecule of HBr reacts with one molecule of NaOH to form one molecule of NaBr and one molecule of water.