This equation is Na2CO3 + 2 HCl -> 2 NaCl + CO2 (gas) + H2O.
there will be no reaction between the two salts
HBr + NaOH = NaBr + H2O. Remember, acid and base = salt + water
NaOH + HBr = NaBr + H2O
NaOH + HCl = H20 + NaCl
NaOH + HCI = H2O + NaCI
NaOH and HCl are the reactants; water and ammonium chloride are the products.
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
hic noah
NaCL + H2O
nacl
NaOH and HCl are the reactants; water and ammonium chloride are the products.
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
hic noah
NaCL + H2O
NaCl
if there is the same number of atoms on both sides e.g Mg + HcI-------------> Mg + HcI^2 (HcI squared) this is an unbalanced reaction because there is more chlorine on the right side than the left side. so when you balance the equation it will look like this: MG + HcI^2------------------>Mg +HcI^2
carbon dioxide
NaCl and H2O
An acid-base reaction