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We can find it by using wheatstone bridge.

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Q: Half deflection method to find galvanometer resistance?
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Related questions

If you want to measure a current greater than the full scale deflection of the constructed ammeter in this case should the resistance in parallel with the galvanometer be increased or decreased?

A: the resistance should be decreased to 1/2 its value for half scale reading or use any ratio [ decrease] to obtain a correct reading.


Is spring constant doubled if a spring is cut into two parts and if yes then why?

if f is applied on L length sprig it will deflect by x distance. When spring is L/2 deflection is also x/2 for same force f.. and K=F/deflection. there for k is inversaly proptional to deflection .. when deflection is half K is double.


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less than half an inch along the longest stretch


A lenght of cirular wire as a resistance of 1 ohms if its the diameter was double its resistance woul be.?

Its resistance would be half , 0.5 ohms is the answer.


What method uses half the fat or flour?

one of them is the creaming method


How does resistance after current?

Assuming you are asking "How does resistance altercurrent?", then the answer is that, for a given value of potential difference, the current is inversely-proportional to the resistance. E.g. doubling the resistance will reduce the current by half.


What happens to the resistance as the area increases?

Double the area means half the resistance. Resistance = resistivity times length / area. Resistivity is a property of the material only.


Split-half method for testing reliability?

advantages of split half reliability


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What happens to the power if the resistance of a circuit doubles and voltage remains the same?

the power will be reduced to the haflf because P=V2/R so when the resistance doubles the power reduced to the half of itsoriginal value


How do you measure ac voltage by using galvanometer?

First rectify the voltage signal then pass it through galvanometer. its reading will give the rms value, so multipy it with form factor to get amplitude of the signal. Form factor for sinusoidal half wave and full wave are 1.11 and 2.22 respectively. One should also take care of voltage drop accross the rectifier diodes in calculation.