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How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
What mass of nitrogen is needed to make 34 grams of ammonia?
To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
How many grams of oxygen are required to burn 100 gram of propane?
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
How many grams are there in 200 g of ammonia?
There are 200 grams of ammonia in 200 grams of ammonia.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
How many grams of Oxygen are needed to completely react with 5.0 grams of butane in a butane lighter?
To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.
What mass of oxygen (O2) is required to react completely with 86.17 grams of C6H14?
The answer is 152 g oxygen.
How many grams of oxygen are need to react with 4.6 grams of titanium chloride?
To find the grams of oxygen needed, we first calculate the molar mass of titanium chloride (TiCl4) and oxygen (O2). Then, we use the molar ratio of TiCl4 to O2 from the balanced chemical equation to find the grams of O2 needed.
How many hydrogen molecules are needed to produce 525 grams of ammonia?
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
