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It depends upon at how much voltage level 400 kvar capacitor bank is used.
It depends on the power factor of the load, but for a load power factor of 0.7 on a 2000 kVA transformer the real power and reactive power are both 1400 kilo (watts and VAR). So a 1400 kVAR capacitor on the load would restore the power factor to 1, allowing 2000 kW to be drawn instead of only 1400 kW.
we can use the Out Put Capacitor Ex Kvar
{| |- | capacitance of the capacitor is mentioned in KVAR. Formula : KVAR = KW*tan@ FOR tan@, First note the power factor & KW without connecting capacitor. The noted power factor is in cos@.Convert the cos@ value in tan@. for ex. If power factor is 0.6, KW = 200 cos@ = 0.6 cos-1 (0.6) = 53.1 tan (53.1) = 1.333 200*1.333 = 266.6 KVAR if you use 266 KVAR capacitor, Then the power factor improves to unity (1.000). |}
When the capacitor kVAR rating is much larger than required, it can cause overcompensation in the power factor of the system, leading to an overvoltage condition. This can result in increased stress on the capacitor itself, as well as on other components in the system. It is important to properly size capacitors to avoid these issues.
Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank. Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank. Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank.
Cable sizing is based on amperage of the load. The rating of the capacitor bank and the voltage at which it operated need to be stated to give an answer.
To find the capacitance in farads of a one kilovolt-ampere reactive (kVAR) capacitor, you can use the formula: ( C = \frac{Q}{V} ) and ( Q = \frac{S}{\omega} ), where ( S ) is the apparent power in volt-amperes, ( \omega ) is the angular frequency in radians per second, and ( V ) is the voltage. Assuming a standard frequency of 60 Hz, ( \omega = 2\pi \times 60 ). A one kVAR capacitor at this frequency typically has a capacitance of approximately 0.0044 farads, or 4400 microfarads.
If the power factor is 0.7 the reactive power equals the real power, so the capacitor should be 1.5 kVAr. That is a reasonable estimate for a small induction motor.
KVAR Kilovolt-Ampere Reactive KVAR Kilovolt-Ampere-Reactance {| ! Acronym ! Definition | Formular for calculation of kvar |}
To determine the number of capacitors needed for KVAR correction for air conditioners, first calculate the total power requirement in kilovolt-amperes (KVA) by converting horsepower (HP) to KVA using the formula: KVA = HP × 0.746. For two 1.5 HP units and one 2.5 HP unit, the total KVA is approximately 3.73 KVA. Then, assess the existing power factor and the desired power factor to calculate the required KVAR for correction using the formula: Required KVAR = KVA × (tan(acos(existing power factor)) - tan(acos(desired power factor))). Finally, select capacitors that match the calculated KVAR.
kvar