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Mol Wt of HCl = 36.461 G/Mole = 36.46 G HCl/Liter
0.2 X 36.461 = 7.2922 Grams HCl/Liter
Since HCl is fuming hydrochloric acid, this would be most difficult to weigh out, so doing it volumetrically is probably a more practical way of doing it. Typical Reagent Grade HCl, called fuming hydrochloric acid, is 36% HCl and has a density of 1.179 g/mL
So 7.2922 Grams HCl X 1.179 Grams/mL = 8.597 mL HCl
So the practical way to do this would be to add some water, perhaps 200 mL, to a 1 Liter Class "A" volumetric flask, then slowly add approximately 8.6 mL of 36% reagent grade HCl.
Swirl the flask and continue to add distilled water to the meniscus.
This is how you would make it up in a lab. Afterwards, you would do a titration against 0.1 N NaOH and do a calculation to determine if you need to adjust the HCl for slight errors. You would then use the corrected N value (normality or Molarity) in using the reagent.
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∙ 11y ago
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∙ 15y agohttp://wiki.answers.com/Q/Why_8.5_ml_requires_to_prepare_1_N_HCl"
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How many moles of HCl in 25ml of 1.0 M HCl?
What you are wanting to do is reduce the concentration so that it is 0.24/1.5 (=0.16) of what it currently is. To get this you need to incrase the ammount of water by 1.5/0.24 (=6.25). So you will need to add (6.25*25)-25 ml of water (the -25 is because you already have 25 ml of water). So your answer is 131.25 ml The only way to get good at these is to practice, it always helps to write down exactly what you have in words and to remember that molar means the ammount in 1000 ml.
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