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No. Since water boils at 212F, at 100F it begins to evaporate. It freezes at 32F.
Celsius is designed with two reference points; The point at which water freezes and the point at which water boils, 0c and 100c respectively. This can be compared to Fahrenheit at 32f and 212f respectively.
There's really only one scientific measurement for temperature, and that's the Kelvin scale. The commonly used systems for weather are Celsius and Fahrenheit. Water freezes at 273K, 0C, and 32F. Water boils at 373K, 100C, and 212F.
Start by taking the number in Fahrenheit and subtracting 32. Then divide the number by 9, and then multiply it by 5. This is how you convert Fahrenheit to Celsius or use the equation C = (F - 32) × 5/9In this case, the answer is about 15.56 degrees Celsius.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
That depends on the organism you're talking about. In general though, life as we know it needs liquid water to survive. That would suggest that the temperature range would fall somewhere around 32F and 212F give or take several degrees depending on a number of variables.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
It is 0C and 32F.
122 degrees F 212-32=180 180 divided by 2= 90 90+32= 122 I am just guessing. It's what my friend told me
A fairly accurate two-point calibration (if the sensing element is submersible) can be achieved by using an ice-water-salt solution to calibrate to 32F, and using boiling water to calibrate to 212F (corrected for atmospheric pressure at your location). If you live in a metric part of the world, your calibration points would be 0C and 100C, of course.
water freezes at 0C or 32F