due to the anomalous behaviour of water.....
The heat of fusion refers to the energy required to change a substance from a solid to a liquid at its melting point. For water to change from ice to liquid water, heat needs to be added, making the heat of fusion a positive value.
Because of the heat of fusion the ice is now water
The heat required to vaporize 500 grams of ice at its freezing point is the sum of the heat required to raise the temperature of the ice to its melting point, the heat of fusion to melt the ice, the heat required to raise the temperature of water to its boiling point, and finally the heat of vaporization to vaporize the water. The specific heat capacity of ice, heat of fusion of ice, specific heat capacity of water, and heat of vaporization of water are all needed to perform the calculations.
Ice is made by bringing water to 32 degrees F, and then continuing to remove the heat of fusion until the water transforms to ice.
The heat of fusion of water, which is the amount of heat energy required to melt one gram of ice at its melting point, is approximately 334 joules per gram. This means that to melt an ice cube, the ice must absorb 334 joules of heat energy per gram to transition from a solid to a liquid state.
The energy absorbed by one gram of ice as it melts is known as the heat of fusion for water. This energy is required to break the intermolecular forces holding the ice molecules together and convert the solid ice into liquid water at its melting point.
Temp is the same, the quantity of heat is not.
The latent heat of vaporisation of water requires more energy. This is because on melting, the intermolecular bonds in water are only weakened whereas on boiling, the bonds are completely broken, which requires a larger amount of energy.
The amount of energy needed to change a given mass of ice to water at constant temperature is called the heat of fusion. This is the heat energy required to change a solid to a liquid at its melting point.
First you need to know at what temp. is the ice?The latent heat of fusion for ice at 32 degrees F is 144 but per pound.This will change 1 pound of ice at 32 degrees F into water at 32 degrees F.It is defined as the amount of heat required for the 1 mole of ice to bring a change in its state, that is, from solid state to liquid state. It is also known as enthalpy of fusion, specific melting point or latent heat of fusion of ice. The particular temperature at which there is a change in the state of the ice is known as the melting point of ice.
To calculate the heat needed to melt a block of ice at its melting point, you need to know the mass of the ice block, the specific heat capacity of ice, and the heat of fusion of ice (or latent heat of fusion). The formula to calculate this heat is Q = m * ΔHf, where Q is the heat energy, m is the mass, and ΔHf is the heat of fusion.
The latent heat of fusion of 1kg water is 334 kJ/kg. (Wikipedia)