If the fibroid is perfectly rectangular, then the area of one of its surfaces is 50.76 cm. That is large for a uterine fibroid.
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
edit: just check answer, answer was wrong
First, set up a few equations...2w + 2l = 54w = l/2With a little manipulation...l = 2wso therefore6w = 54w = 9and, substituting back in,l = 18
12 + 24 + 18 = 54cm (Or 0.54 metres)
False. 54cm = 540mm
9 centimetres,as 54/6 is 9
54cm
yes,it is true...... 5.4mm = 54 cm
is 54cm=5.4mm
if one length is 9cm, the other length must be 6cm to make an area of 54cm. hence the perimeter is 9+9+6+6 = 30cm
57cm X 54cm X 15 cm equals 7,156 square inches.
54cm (almost).